Answer:
Solving quadratic equations can be difficult, but luckily there are several different methods that we can use depending on what type of quadratic that we are trying to solve. The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.
Step-by-step explanation:
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Answer:
6.68, 13.37, 14.95
Step-by-step explanation:
One of the legs is twice as long as the other.
b = 2a
The perimeter is 35.
35 = a + b + c
The triangle is a right triangle.
c² = a² + b²
Three equations, three variables. Start by plugging the first equation into the second and solving for c.
35 = a + 2a + c
c = 35 − 3a
Now plug this and the first equation into the Pythagorean theorem:
(35 − 3a)² = a² + (2a)²
1225 − 210a + 9a² = a² + 4a²
1225 − 210a + 4a² = 0
Solve with quadratic formula:
a = [ -(-210) ± √((-210)² − 4(4)(1225)) ] / 2(4)
a = (210 ± √24500) / 8
a ≈ 6.68 or 45.82
Since the perimeter is 35, a = 6.68. Therefore, the other sides are:
b ≈ 13.37
c ≈ 14.95
Answer:
17
Step-by-step explanation:
Properties used:-
All sides of rhombus are equal therefore in the triangles
EQUAL SIDE OPPOSITE TO ANGLES, ANGLES BECOME EQUAL
then we use alternate interior angles
Then we get,
3x-11=x+23
2x=34
x=17
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