All categories

3 years ago

Which formula gives the average rate of change of f(x) over the interval [8,12]?

Mathematics

2 answers:

Kruka [31]3 years ago

5 0

I think the answer is C hope this would help you

vagabundo [1.1K]3 years ago

3 0

Answer:

$\frac{f(12)- f(8)}{12-8}$

Step-by-step explanation:

the average rate of change of f(x) over the interval [8,12]

The formula for average rate of change of f(x) over the interval [a,b] is

$\frac{f(b)- f(a)}{b-a}$

Given interval is [8,12]

a= 8 and b = 12

So the average rate of change over the interval [8,12] is

$\frac{f(12)- f(8)}{12-8}$

option 3 is correct

You might be interested in

Which is the equation of a line that has a slope of Negative two-thirds and passes through point (–3, –1)?

weqwewe [10]

Answer:

Y=2/3x+1

Step-by-step explanation:

5 0

2 years ago

Kyle was playing a new video game.He scored 128 points on his first game.He scored 305 points on his second game,and 490 on his

Ivahew [28]

First game= 128
Second game= 305
Third game= 490

Add the points per game together.

= 128 + 305 + 490
= 923 points

ANSWER: He scored 923 points during the three games.

Hope this helps! :)

5 0

2 years ago

What is the probability that both ties he chooses are solid white

4vir4ik [10]

Answer:

$\frac{1}{25}$

Step-by-step explanation:

Total outcome is 10

Favorable outcome is 2

The probability to choose solid white tie is $\frac{1}{5}$

The probability that both ties he chooses are solid white is

$\frac{1}{5}$ × $\frac{1}{5}$ = $\frac{1}{25}$

3 0

3 years ago

Tia and her friends are going to the ice skating rink. Each person pays $5 for admission and $5 for food. Write and evaluate a n

s344n2d4d5 [400]

Let the variable for total cost be c and person be p
c = 5x + 5x

3 0

3 years ago

CALCULUS: Determine which function is a solution to the differential equation y ' − y = 0.

Montano1993 [528]

C: none of these are solutions to the given equation.

• If y(x) = e², then y is constant and y' = 0. Then y' - y = -e² ≠ 0.

• If y(x) = x, then y' = 1, but y' - y = 1 - x ≠ 0.

The actual solution is easy to find, since this equation is separable.

y' - y = 0

dy/dx = y

dy/y = dx

∫ dy/y = ∫ dx

ln|y| = x + C

y = exp(x + C )

y = C exp(x) = C eˣ

8 0

2 years ago