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melomori [17]
4 years ago
9

Can someone help me find the domain of this function please ?

Mathematics
1 answer:
ratelena [41]4 years ago
4 0

Answer: It is A=-1<x<-6 is the domain

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find the surface areas of the larger cone and the smaller cone in terms of pi. compare the surface areas using a percent. (the m
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ANSWER :

Surface area of larger cone : 24π units^2

Surface area of smaller cone : 6π units^2

The surface area of the smaller cone is 25% of that of the larger cone.

EXPLANATION :

From the given problem,

AB = 3 is the radius of the larger cone and the slanted height is BC = 5

DE = 1.5 is the radius of the smaller cone and the slanted height is EC = 2.5

Recall the surface area of the cone :

A=\pi r^2+\pi rL

where r = radius and L = slanted height.

For the larger cone, r = 3 and L = 5

\begin{gathered} A=\pi(3)^2+\pi(3)(5) \\ A=24\pi \end{gathered}

For the smaller cone, r = 1.5 and L = 2.5

\begin{gathered} A=\pi(1.5)^2+\pi(1.5)(2.5) \\ A=6\pi \end{gathered}

Comparing the surface areas :

The area of the smaller cone compared to the larger cone is :

\begin{gathered} \frac{smaller}{larger}\times100=\frac{6\pi}{24\pi}\times100 \\  \\ =25\% \end{gathered}

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1 year ago
What it is the quadratic formula ?
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The\ quadratic\ formula\ is\ the\ solution\\\ of\ the\ quadratic\ equation\ ax^2+bx+c=0\\\\Ans.\ \ x= \frac{\big{-b\pm }\sqrt{\big{b^2-4ac}} }{\big{2a}}
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WILL MARK THE BRAINIEST!!! LOTS OF POINTS!! HELP NOW
ElenaW [278]

cos (arctan (1))=

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            never leave a sqrt in the denominator

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sin (arccos (1/2)

arccos (1/2) = 60    take it to the 4th quadrant   -60 degrees

sin (-60)

- sin 60

- sqrt(3)/2




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3 years ago
Find the distance between the points (0, 2) and (4, 5).
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Answer:

it's going to be 5

Step-by-step explanation:

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Add.<br> (2x + 5) + (3x - 7)<br> A) x - 2 <br> B) x + 2 <br> C) 5x - 2 <br> D) 5x + 2
MrRissso [65]
5x - 2. Just combine like terms, and distribute the + to the second term. 
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