ANSWER :
Surface area of larger cone : 24π units^2
Surface area of smaller cone : 6π units^2
The surface area of the smaller cone is 25% of that of the larger cone.
EXPLANATION :
From the given problem,
AB = 3 is the radius of the larger cone and the slanted height is BC = 5
DE = 1.5 is the radius of the smaller cone and the slanted height is EC = 2.5
Recall the surface area of the cone :

where r = radius and L = slanted height.
For the larger cone, r = 3 and L = 5

For the smaller cone, r = 1.5 and L = 2.5

Comparing the surface areas :
The area of the smaller cone compared to the larger cone is :
cos (arctan (1))=
arctan (1) = 45 take it to the third quadrant = add 180 = 225
cos (225) = -1 / sqrt(2)
never leave a sqrt in the denominator
= -1 /sqrt(2) * sqrt(2)/sqrt(2)
= -sqrt(2)/2
sin (arccos (1/2)
arccos (1/2) = 60 take it to the 4th quadrant -60 degrees
sin (-60)
- sin 60
- sqrt(3)/2
Answer:
it's going to be 5
Step-by-step explanation:
5x - 2. Just combine like terms, and distribute the + to the second term.