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pshichka [43]
3 years ago
11

Solve the equation 2x^2-1x=5x

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
4 0
2x² - 1x = 5x
2x² - 1x - 5x = 0
2x²-6x=0
2x(x-3)=0
2x = 0     or    x-3 = 0
x = 0              x = 3

Answer: x=0,  x=3
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PLEASE ANSWER ASAP> WILL MARK BRAINLIEST!!!!!
tekilochka [14]

Answer:

exterior because it's an obtuse triangle.

Step-by-step explanation:

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3 years ago
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An identification code is to consist of 2 letters followed by 3 digits. how many different codes are possible if repetition is p
Vedmedyk [2.9K]
I like the 'question mark' at the end:

26 letters (English), 10 digits (0,1,...9)

26*26*10*10*10 = 676000

Now, this was for LLDDD (Letter Letter Digit Digit Digit)

It seems this is the order they want. Other wise, one should multiply by all the combinations in the order: LDLDD, DLLDD, etc ... (10 combinations), but again it seems they want this LLDDD

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5 0
3 years ago
Whats the reciprocal of 1 8/11
Juliette [100K]

First, change the mixed fraction into improper fraction. Change the whole number into a fraction, and add.

1 8/11 = 11/11 + 8/11 = 19/11

To find the reciprocal, flip the fraction.

The reciprocal of 19/11 is 11/19

hope this helps

8 0
3 years ago
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a party of 7 comes into your restaurant and says they want to split the bill evenly 7 ways their total is $247.79 what does each
Finger [1]

Answer:

each costumer owe $35.40

Step-by-step explanation:

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u get 35.40.

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6 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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