Ask question

Ask question

All categories

3 years ago

14

Lisa and Ann are eating a box of crackers. Lisa eats 3/6 of the box, and Ann eats 1/4 of the box. How much of the box did the tw

o girls eat together?

1 answer:

sasho [114]3 years ago

7 0

Answer:

the girls ate $\frac{3}{4}$ of the box

Step-by-step explanation:

$\frac{3}{6} = \frac{1}{2} = \frac{2}{4} ,,,\frac{1}{4} +\frac{2}{4} =\frac{3}{4}$

You might be interested in

Find a value of x that is a solution to 5(x – 3) = x + 13. Describe how you found the solution.

Ann [662]

Answer:

x=7

because distributive property and addition and subtraction

7 0

3 years ago

Read 2 more answers

20a+12a-8 simplified

bixtya [17]

That would 32a - 8, Good Luck!

7 0

3 years ago

Read 2 more answers

Licemer1 [7]

Answer will be A, and if you need help with math work Connects is a great app to use

8 0

3 years ago

Help please <br> help ..............................................

postnew [5]

Rs 9600 pls give Brainlyest

4 0

3 years ago

Read 2 more answers

Calculating the degrees of freedom, the sample variance, and the estimated standard error for evaluations using the t statistic

Yuliya22 [10]

Answer:

a) For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

b) $s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

c) For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

Step-by-step explanation:

Part a

For the first part we have a sample of n =10 and we want to find the degrees of freedom, and we can use the following formula:

$df = n-1= 10-1=9$

d.9

Part b

From a sample we know that n=41 and SS= 600, where SS represent the sum of quares given by:

$SS = \sum_{i=1}^n (X_i -\bar X)^2$

And the sample variance for this case can be calculated from this formula:

$s^2 = \frac{SS}{n-1}= \frac{600}{41-1}= 15$

a.15

Part c

For this case we have the sample size n = 25 and the sample variance is $s^2 =400$ , the standard error can founded with this formula:

$SE = \frac{s^2}{\sqrt{n}}= \frac{400}{\sqrt{25}}= 80$

8 0

3 years ago