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3 years ago

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Lisa and Ann are eating a box of crackers. Lisa eats 3/6 of the box, and Ann eats 1/4 of the box. How much of the box did the tw

o girls eat together?

1 answer:

sasho [114]3 years ago

7 0

Answer:

the girls ate $\frac{3}{4}$ of the box

Step-by-step explanation:

$\frac{3}{6} = \frac{1}{2} = \frac{2}{4} ,,,\frac{1}{4} +\frac{2}{4} =\frac{3}{4}$

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We can use the FOIL method to simplify.

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2 years ago

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Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y

kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

M is the sample mean weight of the wild mountain lions ( $\frac{69 +104 +125 +129+60 +64}{6} =91.8$ )

ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)

s is the standard deviation of the sample(31.4)

N is the sample size (6)

Thus, ME= $\frac{1.30*31.4}{\sqrt{6} }$ ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

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