The area of the given right triangle is: 22.5 cm².
<h3>How to Find the Area of a Right Triangle?</h3>
The area of a right triangle with a base of "b" and an height of "h" can be determined using the following formula:
Area of triangle = 1/2bh = 1/2(base)(height).
Given that the right triangle has the following dimensions:
Height (h) = 5 cm
Base (b) = 9 cm
Area of triangle = 1/2bh = 1/2(5)(9)
Area of triangle = 1/2(45)
Area of triangle = 22.5 cm²
Thus, the area of the right triangle is: 22.5 cm².
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Answer:

Step-by-step explanation:
has the form
known as a difference of squares. It factors into (a+b)(a-b). To find a and b you take the square root.


The factored for is (a+b)(a-b).
In this case, it is 
Answer:
x=75
Step-by-step explanation:
642,000 is rounded it the nearest thousand
Answer:
70√2 units²
Step-by-step explanation:
(see attached for reference notes on parallelograms)
we are given ABCD is a parallelogram where
Short Length, AB = 10 units
Long Length, BC = 14 units
Angle A = 45°
The area of the parallelogram is hence,
= AB x BC sin 45°
= 10 x 14 x sin 45
= 140 sin 45° (recall from special angles, that sin 45° = 1/√2)
= 140/√2 (remove radical from denominator by multiplying by √2/√2)
= (140/√2) x (√2/√2)
=70√2 units²