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Luba_88 [7]
3 years ago
12

Difference in length between 3 3/4 and 4 2/3

Mathematics
1 answer:
Natalija [7]3 years ago
3 0
The answer is listen on this link
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PLEASE HELP!!!
Fed [463]

Answer:

b -17

Step-by-step explanation:

−a^2 − 3b^3 + c^2 + 2b^3 − c^2 =

= -(3²) - 3(2³) + (-3)² + 2(2³) - (-3)²

= -9 - 3(8) + 9 + 2(8) - 9

= -9 - 24 + 9 + 16 - 9

= -17

8 0
2 years ago
How many times greater is the value of 3 in the product of 34 × 10000 in the value of 3 in 34
nika2105 [10]

Answer:

It is 4 times greater.

Step-by-step explanation:

6 0
3 years ago
5/4*6/25+6/5 ill even give brainliest
saul85 [17]

Answer:

1.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Need to pick three options. please need help on this​
disa [49]
The 4th one is the answer
3 0
3 years ago
Two boards, one four inches wide and the other six inches wide, are nailed together to form an X. The angle at which they cross
Sunny_sXe [5.5K]

Answer:

The area of the unpainted region on the four inch board = 160·√3 in.²

Step-by-step explanation:

Here we have that the boards are crossing each other on their flat sides Therefore, when the boards are separated, the area of the unpainted region is the area of a parallelogram

The dimensions of the formed parallelogram are;

Interior angles = 60° and 120° (adjacent angles of a parallelogram)

Height, h of parallelogram formed = 4 inches

From the angle of crossing of the parallelogram, we have;

Angle between the width or perpendicular cross section of the 6 inches board and the angle of crossing of the two boards = 90° - 60° = 30°

Therefore, length of base, b of the parallelogram formed by the unpainted region is given as follows;

b = \frac{60}{cos(30)}  = 40\cdot \sqrt{3} \ inches

Therefore, the area of the parallelogram = b × h = 4 × 40·√3 = 160·√3 in.²

Hence, the area of the unpainted region on the four inch board = 160·√3 in.².

3 0
3 years ago
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