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Novay_Z [31]
3 years ago
7

Given that RT ≅ WX, which statement must be true?

Mathematics
2 answers:
Wittaler [7]3 years ago
4 0

Answer:RT is congruent to WX

Step-by-step explanation:

Ivan3 years ago
3 0

Answer: RT

Step-by-step explanation:

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(a^2-b^2) (c^2-d^2) +4abcd​
Vikki [24]

a^{2}  {c}^{2}  -  {a}^{2}  {d}^{2}  -  {b}^{2}  {c}^{2}  +  {b}^{2}  {d}^{2}  + 4abc

5 0
3 years ago
Does anyone know geometry?
Naily [24]

Answer:

286m²

Step-by-step explanation The formula to find the surface area of a rectangular prism is A = 2wl + 2lh + 2hw, where w is the width, the l is the length, and the h is the height.

8 0
3 years ago
Read 2 more answers
Someone please help!!! Due tonight, I’ll give brainliest!!!
Ad libitum [116K]

Answer:

2 * 0.75 + 0.50 + 4 * 1.25

$7.00

Step-by-step explanation:

Expression

2 * 0.75 + 0.50 + 4 * 1.25

Evaluate

1.50 + 0.50 + 5.00

$7.00

6 0
3 years ago
Can someone plz help with this asap
Lera25 [3.4K]

Answer:

Horizontal lines are parallel to the x-axis

The answer is the second option

6 0
3 years ago
Please help if you understand!! I hope everyone has a great day or is having a great day​
Monica [59]

Answer:

Firstly, notice the relationship the two triangles have. They have conjoining ends that form vertical angles (looks like a middle x). Vertical angles are equivalent in measure of degrees.

Secondly, notice that the triangle on the right side is a right triangle. One of its angle's measurements are also given; 40 degrees. If you know that the sum of a triangle's angles equal 180 degrees, then simply subtract the known angles measurements from 180.

180-(90+40)=  180-130=50.

Therefore, the vertical angles measurement is equivalent to 50 degrees.

Apply the principle of the sum of all angles in a triangle equivalent to 180 degrees to the left triangle, and you will be able to find the measurement of the "?" angle.

180-(50+25)= 180-75=105

SO HERE IS YOUR ANSWER= 105 degrees is the value of the angle marked with a "?"

I hope you are having a great day too;)!

8 0
3 years ago
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