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aliya0001 [1]
2 years ago
8

What is 3a squared add 7 a

Mathematics
1 answer:
vfiekz [6]2 years ago
3 0
The answer is:  " 9a² + 7a " .
_________________________________
Note:    (3a)² + 7a = (3a)*(3a) + 7a = 9a² + 7a .
_________________________________
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3 0
2 years ago
Solving for b in this problem
kipiarov [429]

Answer:

b = 3

Step-by-step explanation:

1. Subisitute P, a, and c (P = 41, a = 19, c = 19 ) into the equation:

P = a + b + c -> 41 = 19 + b + 19

2. Combine like terms:

41 = 38 + b

3. Isolate the variable by subtratcing 38 from both sides

41 - 38 = 38 -38 + b -> 3 = b

6 0
3 years ago
Read 2 more answers
How do you find the exact cosine or sine value for each given measure of an angle?
Helen [10]

Answer:

REMEMBER:

to find the sine, cosine on the unit circle:

cos a = coordinate value x

sin a = coordinate value of y

Step-by-step explanation:

I'm not sure y'all but i hopes this helps just a remember.

5 0
3 years ago
Compare the process of solving |x – 1| + 1 &lt; 15 to that of solving |x – 1| + 1 &gt; 15. Check all of the following you includ
zepelin [54]

The required Comparison of the inequalities are

  • The |x – 1| + 1 > 15 represents the value of x lies between 13<x<15.

The range of values encompassing the region's junction is (-13, 15).

  • If x is more than or equal to 15, then x-11+1>15 indicates the value of x is greater than or equal to 13. None of the regions in the intersection are empty.

<h3>What is inequality?</h3>

When comparing two numbers, an inequality indicates whether one is less than, larger than, or not equal to the other.

We take into account the various variables of the inequality

|x – 1| + 1 > 15

Therefore

|-x-1|+1-1<15-1

|-x-1|-1 <14

13<x<15

The required region lies between the inequality -13 <x< 15.

Simplify the inequality Ix-11+1 > 15 we get,

|x-1|+1 > 15

|x+1| +1-1 >15-1

|x-1| > 14

x> 15  

x<-13

  • If x has a value between -13 and x + 15, then the expression "|x-1|+1+115" is true. The range "(-13, 15)" contains the intersection of the region.
  • If "|x-1|+1>15" then either "x >15" or "x-13" applies to the value of x. This region's intersection is unoccupied.

Read more about inequalities

brainly.com/question/20383699

#SPJ1

7 0
2 years ago
Find the slope of the line passing through the points (1,-5) and (4,1).
e-lub [12.9K]
<h3>Answer:</h3><h3>The equation for the slope of a line, given two coordinate points, (x1,y1) , (x2,y2), is (y2-y1)/(x2-x1)  </h3><h3>  So we get slope = (1-(-5)) / (4-1)  = 6/3 = 2</h3><h3>A is your correct answer.</h3>

Hope this helps! please consider marking my answer the brainliest :)

4 0
3 years ago
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