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Deffense [45]
3 years ago
14

A construction company is planning to bid on a building contract. The bid costs the company ​$1400. The probability that the bid

is accepted is 1/4. If the bid is​ accepted, the company will make ​$17,600 minus the cost of the bid.
What is the expected value in this​ situation?
Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

$3,000

Step-by-step explanation:

There two possible outcomes:

There is a 3/4 chance that the bid is rejected for a value of -$1,400

There is a 1/4 chance that the bid is accepted for a value of $17,600 - $1,400.

The expected value of the situation is:

E = \frac{3}{4}*(-1,400)+\frac{1}{4}*(17,600-1,400)\\E=\$3,000

The expected value is $3,000.

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I NEED HELP PLEASE, THANKS!!!
denpristay [2]

Answer:

C. 105 mm^2

Step-by-step explanation:

<em><u>The formula for a regular polygon is:</u></em>

<em><u /></em>\frac{1}{2}pa   → p is the perimeter and a is the apothem

\frac{1}{2} (42)(5)

105

3 0
3 years ago
An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry ou
Katyanochek1 [597]

Answer:

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

p_v =P(t_{(5)}  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

Step-by-step explanation:

Data given and notation  

The mean and sample deviation can be calculated from the following formulas:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (x_i -\bar X)}{n-1}}

\bar X=29.35 represent the sample mean  

s=1.365 represent the sample standard deviation  

n=6 sample size  

\mu_o =30 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 30 or no, the system of hypothesis are :  

Null hypothesis:\mu \geq 30  

Alternative hypothesis:\mu < 30  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{29.35-30}{\frac{1.365}{\sqrt{6}}}=-1.17  

P-value  

We need to calculate the degrees of freedom first given by:  

df=n-1=6-1=5  

Since is a one-side left tailed test the p value would given by:  

p_v =P(t_{(5)}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.  

We can say that at 5% of significance the true mean is not significantly less than 30 so then the claim that true average fuel efficiency is (at least) 30 mpg makes sense

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3 years ago
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AysviL [449]

The answer is B you divide 0.035 from 16 then subtract that number with 16 with 15.44 you divide it by 0.0425 and with the answer subtract 15.44 with it

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3 years ago
Does Anyone know how many time can 4 go into 0
velikii [3]
4 can go into 0 0 times
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3 years ago
Read 2 more answers
Hii i’ll give brainliest please help thanks :)
Juliette [100K]

Answer:

Step-by-step explanation:

The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest.

Hope this help

6 0
3 years ago
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