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Deffense [45]
3 years ago
14

A construction company is planning to bid on a building contract. The bid costs the company ​$1400. The probability that the bid

is accepted is 1/4. If the bid is​ accepted, the company will make ​$17,600 minus the cost of the bid.
What is the expected value in this​ situation?
Mathematics
1 answer:
liubo4ka [24]3 years ago
7 0

Answer:

$3,000

Step-by-step explanation:

There two possible outcomes:

There is a 3/4 chance that the bid is rejected for a value of -$1,400

There is a 1/4 chance that the bid is accepted for a value of $17,600 - $1,400.

The expected value of the situation is:

E = \frac{3}{4}*(-1,400)+\frac{1}{4}*(17,600-1,400)\\E=\$3,000

The expected value is $3,000.

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Answer:

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Step-by-step explanation:

Michelle is in less debt than John

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3 years ago
Peter is trying to set a new record for pizza deliveries. His previous record is 20 pizzas in one hour. He has already delivered
Arlecino [84]
We know that
<span>Peter has already delivered </span><span> 2 pizzas in 5 minutes
so
1 hour-------> 60 minutes
</span><span>time left------> 60 minutes - 5 minutes--------> 55 minutes 

</span>pizzas to deliver to beat his previous record----------> 20-2------> 18 pizzas

therefore
in the next 55 minutes

if the

<span>average per minute = (18/55) pizzas /minute
</span>Pete beat his previous record
<span>
 </span>average per minute  > (18/55) pizzas /minute
Pete overcome the previous record

 average per minute  < (18/55) pizzas /minute
Pete will not match the previous record
5 0
3 years ago
The functions f(x) and g(x) are shown.
erastova [34]

The function f(x) takes on the value 2 when x =  -7 and x = -3, and thus the corresponding points are (-7,2) and (-3,2).

The points where g(x) = 0 are called "roots" or "solutions," and is (3,0).

f(x) > g(x)  on the approx. interval (-9, -3/4).

7 0
3 years ago
You have 19 shirts to choose from, 5 pants, and 2 pairs of shoes. How many different outfits can you make?
Yanka [14]
if this is a homework question, they probably mean the pedestrian 20 outfit answer.
5 0
3 years ago
find two consecutive odd integers whose product is 1 less than 6 times their sum. Domain for the smallest : {-1, 1, 11}
inn [45]
Let x be the 1st odd number, and x+2 the second odd consecutive number:

(x)(x + 2) = 6[((x) + (x+2)] -1
x² + 2x = 6(2x + 2) - 1

x² + 2x = 12x +12 - 1
And x² - 10x - 11=0

Solve this quadratic expression:

x' = [+10 +√(10²- 4.(1)(-11)]/2  and x" = [+10 -√(10²- 4.(1)(-11)]/2

x' = [10 + √144]/2      and  x" = [10 - √64]/2

x' = (10+12)/2    and x" = (10-12)/2

x = 11 and x = -1

We have 2 solutions that satisfy the problem:

1st for x = 11, the numbers at 11 and 13
2nd for x = - 1 , the numbers are -1 and +1
If you plug each one in the original equation :(x)(x + 2) = 6[((x) + (x+2)] -1
you will find that both generates an equlity


6 0
3 years ago
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