If one angle is 8 times bigger than the other, the bigger angle's measure would be 8x and the smaller angle's measure would be x. 8x+x=90. This simplifies to 9x=90. To find x, you divide 9 from 90, making x=10. This means the smaller angle (Angle 2) is 10° and the bigger angle's (Angle 1) is 8 times 10, so it is 80°.
<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>
1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)
2) Angles ABC and CDE are right angles (perpendicular lines form right angles)
3) Angles ABC and CDE are equal (all right angles are equal)
4) Angles ACB and DCE are equal (vertical angles are equal)
5) Triangles ABC and EDC are congruent (ASA)
<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>
6) AB = DE (corresponding parts of congruent triangles are equal)
Answer:
x = -3, x = 0 is a extraneous solution
Step-by-step explanation:
Step 1: Cross-multiply
3x² = 4x² + 3x
Step 2: Isolate <em>x</em>'s
0 = x² + 3x
Step 3: Factor
0 = x(x + 3)
Step 4: Find roots
x = 0, -3
Step 5: Double check work
Plug in both to see if they both work. Only x = 0 should be extraneous. We now have our answer!
