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Answer:
- Constraints: x + y ≤ 250; 250x +400y ≤ 70000; x ≥ 0; y ≥ 0
- Objective formula: p = 45x +50y
- 200 YuuMi and 50 ZBox should be stocked
- maximum profit is $11,500
Step-by-step explanation:
Let x and y represent the numbers of YuuMi and ZBox consoles, respectively. The inventory cost must be at most 70,000, so that constraint is ...
250x +400y ≤ 70000
The number sold will be at most 250 units, so that constraint is ...
x + y ≤ 250
Additionally, we require x ≥ 0 and y ≥ 0.
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A profit of 295-250 = 45 is made on each YuuMi, and a profit of 450-400 = 50 is made on each ZBox. So, if we want to maximize profit, our objective function is ...
profit = 45x +50y
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A graph is shown in the attachment. The vertex of the feasible region that maximizes profit is (x, y) = (200, 50).
200 YuuMi and 50 ZBox consoles should be stocked to maximize profit. The maximum monthly profit is $11,500.
Answer:
Easy peasy
Step-by-step explanation:
7+(n-1)5
The formula is principal x ( 1+ interest rate)^ number of years
5%:
20,000 x 1.05^3 = $23152.50 total
Interest = 23152.50-20000= $3,152.50
10%
20000 x 1.10^3 = $26,620.00
Interest = 26620-20000 = $6,620
12%
20000 x 1.12^3 = $28,098.56
Interest = 28098.56-20000 = $8.098.56
The answer is C).
If each cost .19 and ounce you would use x to indicate the unknown value therefore you will have .19x. the x is the amount of ounces which is 8. So .19 x 8 which equals 1.52.
The total cost for one can is: $25.41.
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Let us assume that we want to know the total cost of ONE CAN.
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To calculate our answer:
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$ 23.97 + [ (6/100) * 23.97)] = Our answer, in dollars.
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Note: "6%" = 6/100 = 0.06
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Rewrite as:
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$ 23.97 + [ (6/100) * 23.97)] = our answer, in dollars;
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$ 23.97 + (0.06 * 23.97)
= $ 23.97 + 1.4382
= $ 25.4082 ; Round to decimal places, to get:
<span>→ $ 25.41
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