Answer:
1128.
Explanation:
The dominant taster phenotype is 1482.
The recessive taster phenotype = 2400 – 1482 = 918
.
Recessive phenotypes = 2400 – 1482 = 918
The recessive phenotype frequency = q² = 918 / 2400 = 0.38.
the recessive allele frequency q = √0.38 = 0.62.
The dominant allele frequency, p = 1-q = 1- 0.62 = 0.38
The heterozygous frequency = 2pq = 2 ×0.38 × 0.62 = 0.47
.
The heterozygous individual in the population = 0.47 × 2400 = 1128.
Thus, the answer is 1128.
Answer:
c. ¼ heavy, ¾ light
Explanation:
DNA replication follows semi conservative model which means that both the strands separate during replication and the newly formed DNA molecule has one old and one new strand. If instead of semi conservative, conservative mechanism is used, old strands will not separate from each other and the two newly synthesised DNA strands will come together to form a DNA molecule.
Here the cells were first grown in heavy 15N medium so all the DNA molecules had 15N and thus were heavy. Then the cells were transferred to 14N medium where only lighter 14N were available for replication process.
In first generation, 14N DNA molecules were synthesised from 15N DNA molecules so 1/2 DNA molecules were 15N and other half were 14N. In the second generation, 14N molecules will give rise to new 14N molecules and 15N molecules will also give rise to 14N molecules hence 1/4 molecules will be 15N (heavy) and 3/4 will be 14N (light).
Answer:
The four stages of the animal life cycle are birth, growth, reproduction and lastly, death. All these animal species go through these stages, however, they manifest differently throughout the animal kingdom.
Answer:
the answer is B (ignore this part its for 20 characters)
