Mean=5
sd=2
Using Z(x)=(x-mean)/sd
Z(2)=(2-5)/2=-1.5
Z(6)=(6-5)/2=0.5
Therefore
probability of finding a spot between 2 and 6 minutes is
P(x<6)-P(x<2)
=P(Z<0.5)-P(Z<-1.5)
=0.6915-0.0668
=0.6247
=>
More than half of the students (62.5%) finds a space between 2 and 6 minutes.
Answer:
$6.96
Step-by-step explanation:
5.25% of 5.79
5.79 × 5.25/100 = $0.303975 or $0.30
15% of 5.79
5.79 × 15/100 = $0.8685 or $0.87
total
$5.79 + $0.30 + $0.87 = $6.96
Hi
Bhrkhgabdjvdlsihsldvasdlwdwlij
The answer is c I know because I had that problem two
Answer:
12 feet
Step-by-step explanation:
Same length, double width will give double area
Width = 2×6 = 12