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pogonyaev
3 years ago
6

A baseball manager has 11 players of the same ability. How many 9 player starting lineups can he

Mathematics
1 answer:
Lana71 [14]3 years ago
4 0

Answer:

55

Step-by-step explanation:

Combination will be used here as teams are a group.

So using combination:

<em>No. of combination of 'n' things taken 'r' at a time</em>

<em>\limits^n {C} \,_r= \frac{n!}{r! (n-r)!}</em>

here n = 11 ,

r = 9

11<em>C</em>9 <em>=  \frac{11!}{9! (11-9)!} = \frac{11!}{9! (2!)}</em>

11<em>C</em>9<em> =</em><em> 55</em>

<em>Which are the possible 9 player starting lineups</em>

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