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4 years ago

How to solve this equation: 3x+y=-2

Mathematics

1 answer:

Ann [662]4 years ago

5 0

You have to do the -2 minus 3X and you will get your

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If the divisor is 4 and the quotient is 8, what is the dividend ?

kolbaska11 [484]

<h3>If the divisor is 4 and the quotient is 8, Then, dividend is 32</h3>

<em><u>Solution:</u></em>

Given that,

Divisor = 4

Quotient = 8

To find: dividend

We know that,

$Dividend \div divisor = quotient$

Therefore,

$Dividend \div 4 = 8\\\\Dividend \times \frac{1}{4} = 8\\\\Dividend = 8 \times 4\\\\Dividend = 32$

Thus, dividend is 32

3 0

3 years ago

Write an equation for the description <br><br> a number x increased by 16 is 118.

noname [10]

Answer:

x +16 = 118

Step-by-step explanation:

A number(unknown ) = x

Increased = +

Merge all together you have

$x + 16 = 118$

Tip ; If you solve the equation you will get 102 as an answer. 102 +16 =118 .

SO the equation is correct .☻

6 0

3 years ago

The concentration C (in mg/dl), of a certain antibiotic in a patient's bloodstream is given by C(t)=50 t /(t^2 + 25) where t is

marishachu [46]

Given that the concentration has been modeled by the formula:
C(t)=50t/(t^2+25)
where:
t is time in hours.
The concentration after 5 hours will be given by:
t= 5 hours
plugging the value in the equation we get:
C(5)=(50(5))/(5^2+25)
simplifying the above we get:
C(5)=250/(50)=5 mg/dl

Answer: 5 mg/dl

8 0

3 years ago

9x-7=-7<br><img src="https://tex.z-dn.net/?f=9x%20-%207%20%3D%20-%207" id="TexFormula1" title="9x - 7 = - 7" alt="9x - 7 = - 7"

scZoUnD [109]

Answer:

x= 0

Step-by-step explanation:

Here in this question, we are given a linear equation of single variable x, and we have to solve the equation for x.

The given equation is 9x -7= -7 ....... (1)

Now, taking all the constant terms to the right side of the equation and all the x terms to the left side of the equation.

Hence, the equation becomes

9x = -7 +7

⇒ 9x =0 {Since, -7 and 7 cancels each other}

⇒ x= 0/9= 0 (Answer) {Since zero divided by any number is equal to zero}

7 0

3 years ago

Determine the point of intersection of right bisectors in a triangle ∆ with vertices A (-3, 5), B (1, 1) and (−7, −3). Find the

iris [78.8K]

Answer:

Point of intersection (-11/3 , 1/3)

All distances from the vertices are $\frac{10\sqrt{2} }{3}$

Step-by-step explanation:

The vertices of the triangle is A(-3,5) , B (1,1) and C (-7,-3)

We need to find the perpendicular bisector of the triangle first

let's take one side connecting A and B

mid point of A and B = (-1,3)

Slope of the line joining A and B = -1

slope of perpendicular to line joining A and B = 1

equation of line passing through (-1,3) with slope 1

y - 3 = 1(x-(-1))

y -3 = x+1

x-y = -4 ............(1)

similarly

mid point joining B and C = (-3,-1)

slope perpendicular to line joining B and C = -2

Equation of perpendicular bisector of line joining B and C =

y +1 = -2(x +3 )

y+1 = -2x -6

2x+y = -7 ..........(2)

On solving 1 and 2

x= -11/3 , y= 1/3

Distances

From A = $\frac{10\sqrt{2} }{3}$

From B = $\frac{10\sqrt{2} }{3}$

From C = $\frac{10\sqrt{2} }{3}$

7 0

3 years ago