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adelina 88 [10]
3 years ago
7

How to solve this equation: 3x+y=-2

Mathematics
1 answer:
Ann [662]3 years ago
5 0
You have to do the -2 minus 3X and you will get your
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A $65 meal is put on the table. The couple plans on leaving an 18% tip. How much should be left altogether?
elena-14-01-66 [18.8K]

Answer:

76.70

Step-by-step explanation:

8 0
3 years ago
A car travels about 25 miles on 1 gallon of gas. About how far can the car travel on 8 gallons of gas?
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The answer is
8x25 = 200 miles
4 0
3 years ago
The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative
vagabundo [1.1K]

Considering the vertex of the parabola, the correct statement is given by:

The range of the function is all real numbers less than or equal to 9.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

  • x_v = -\frac{b}{2a}
  • y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point, which means that the range is all real numbers less than or equal to y_v.
  • If a > 0, the vertex is a minimum point, which means that the range is all real numbers greater than or equal to y_v.

In this problem, we have that:

  • a = -1 < 0, hence the vertex is a maximum point.
  • The vertex is (-2,9).

Hence the range is described by:

The range of the function is all real numbers less than or equal to 9.

More can be learned about the vertex of a parabola at brainly.com/question/24737967

#SPJ1

5 0
2 years ago
All of these ODEs model a system with a spring, mass and dashpot.
Wewaii [24]

Answer:

− 3 y ' ' − 3 y ' + 3 y = 0 : over-damped

− 2 y ' ' − 4 y ' + 1 y = 0 : over-damped

1 y ' ' + 7 y ' + 5 y = 0: over-damped

Step-by-step explanation:

Using the characteristic equation you can express a differential equation of order n as an algebraic equation of degree n:

a_ny^n+a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

This differential equation will have a characteristic equation of the form:

a_nr^n+a_n_-_1r^{n-1}+...+a_1r+a_o=0

Now, you can classify the solution for a differential equation using a simple method. In order to do it, you just need to use the discriminant.

  • If the discriminant is greater than zero, the solution is over-damped

  • If the discriminant is less than zero, the solution is under-damped

  • If the discriminant is equal to zero, the solution is critically damped

So, given the differential equation:

-3y''-3y+3y=0

Which has characteristic equation of the form:

-3r^2-3r+3=0

The quadratic polynomial of the form:

ar^2+br+c=0

Has discriminant:

Disc=b^2-4ac

In this case:

a=-3\\b=-3\\c=3

So:

Disc=(-3)^2-4(-3)(3)=9-(-36)=45

In this case:

Disc=45>0

Therefore the solution is over-damped.

Now, given the differential equation:

-2y''-4y'+1y=0

Which has characteristic equation of the form:

-2r^2-4r+1=0

The quadratic polynomial of the form:

ar^2+br+c=0

Has discriminant:

Disc=b^2-4ac

In this case:

a=-2\\b=-4\\c=1

So:

Disc=(-4)^2-4(-2)(1)=16+8=24

In this case:

Disc=24>0

Therefore the solution is over-damped.

Finally, given the differential equation:

1y''+7y'+5y=0

Which has characteristic equation of the form:

1r^2+7r+5=0

The quadratic polynomial of the form:

ar^2+br+c=0

Has discriminant:

Disc=b^2-4ac

In this case:

a=1\\b=7\\c=5

So:

Disc=(7)^2-4(1)(5)=49-20=29

In this case:

Disc=29>0

Therefore the solution is over-damped.

6 0
3 years ago
Rewrite the equation in slope-intercept form. x=4y+2
Dafna1 [17]

Answer:

y = x/4 - 1/2

Step-by-step explanation:

Slope-Intercept Form: y = mx + b

Step 1: Write equation

x = 4y + 2

Step 2: Subtract 2 on both sides

x - 2 = 4y

Step 3: Divide both sides by 4

x/4 - 1/2 = y

7 0
3 years ago
Read 2 more answers
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