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weqwewe [10]
3 years ago
12

Twice a number divid by 6 is 42

Mathematics
2 answers:
il63 [147K]3 years ago
8 0
A number=x

2x/6=42
2x=252 by multiplying both sides by 6
x=126 by dividing both sides by 2 to isolate the variable
Natalija [7]3 years ago
3 0
Let’s call this number ‘n’.

Twice a number is 2n.

2n / 6 = 42

2n = 252

n = 126.
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(Please show step by step workings)
matrenka [14]

Answer:

a. They will need $90,000.00 for the down payment

b. The mortgage amount (principal) will be $360,000.00

c. The monthly principal payment will be $1,500,00

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d. The total interest they will pay: $152,256.00

Step-by-step explanation:

house price= $450,000

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20-year mortgage

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a. How much they will need for the down payment?

The down payment (DoP) is 20% of the house price

DoP= 20% de $450,000

DoP= 0.20*450,000

DoP= $90,000

b. What will be the mortagage amount (the principal)?

The mortgage amount (MoA) (principal) is the difference between the house price and the down payment.

MoA= $450,000 - $90,000

MoA= $360,000

c. How much will their monthly payment be for the principal and interest?

This equation represents the monthly payment (M):

M=P \frac{r(1+r)^{n} }{(1+r)^{n}-1}

where

P= the principal = $360,000

r= monthly interest rate = 3,75% divided by 12 = 0,31%

n= number of payments = 20 years multiplied by 12 months = 240

Let´s input these data into the equation:

M= 360,000\frac{0.0031(1+0.0031)^{240} }{(1+0.0031)^{240} -1}

M= 360,000\frac{0.0031(1.0031)^{240} }{(1.0031)^{240} -1}

Solving the equation:

M= $2,134.40

the principal component of this M would be

$360,000 divided by the 240 months

So, the principal component of M = $1,500.00

And the interest component of M is the difference

$2,134.40 - $1,500.00

So, the interest component of M = $634.40

d. How much total interest will they pay if they take the full 20 years to pay off the mortgage?

With every payment, they will be paying:

$634.40 per month, multiplied by 240 months

The total interest will be $152,256.00

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I think it would be 1462 yards
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2 years ago
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If the input value is negative, the output value is always positive.  We know this because the negative sign before the 4z will always reverse the negativity of the number that is plugged in.
6 0
3 years ago
The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.
devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z\leq 1.72). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15)  from 1. Therefore, we have 1- P(Z\leq -1.09). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

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3 years ago
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bezimeni [28]

Answer:

First, third, and fourth one would be the answers.

4 0
3 years ago
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