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insens350 [35]
3 years ago
11

Identify the data set that could be quadratic. HELP ASAP!!

Mathematics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

the 3rd one (:

Step-by-step explanation:

You might be interested in
How do you do this question?
erik [133]

Step-by-step explanation:

Use the first fundamental theorem of calculus.

∫₆¹⁰ f'(x) dx = f(10) − f(6) = 8 − 8 = 0

5 0
3 years ago
Honestly I dont know how to do this just please help me
V125BC [204]
F(x) = 3x - 2
f(8) = 3(8) - 2
f(8) = 24 - 2
f(8) = 22
f(-5) = 3(-5) - 2
f(-5) = -15 - 2
f(-5) = -17
f(8) - f(-5) = 22 - (-17)
f(8) - f(-5) = 39
Hope this helped! Good luck! :)
7 0
3 years ago
???????????????????????
drek231 [11]

Answer:

x ≅ 7

Step-by-step explanation:

cos(67°) = x/18

x = 18cos(67°) ≅ 7

7 0
2 years ago
Which expression is equivalent to 4(x^3)(2x)^-4
AVprozaik [17]

Answer:

=\frac{4x^{3}}{16 x^{4}}

Step-by-step explanation:

4(x^{3} )(2x)^{-4}

=\frac{4x^{3}}{(2x)^{4}}

=\frac{4x^{3}}{2^{4} x^{4}}

=\frac{4x^{3}}{16 x^{4}}

3 0
3 years ago
If sin θ = 2 over 7 and tan θ > 0, what is the value of cos θ?
sergey [27]
Sin θ = 2 / 7
tan θ > 0
cos θ = ?

sin θ = opposite / hypotenuse
tan θ = opposite / adjacent
cos θ = adjacent / hypotenuse

short leg = opposite = 2
hypotenuse = 7
long leg = adjacent = ?

adjacent = √(7² - 2²)
adjacent = √(49 - 4)
adjacent = √45
adjacent = √9 * 5
adjacent = 3 √5

cos θ = adjacent / hypotenuse
cos θ = 3√5 / 7
6 0
3 years ago
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