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kirza4 [7]
2 years ago
11

Use the graph to solve the equation-2x+7=3x-3

Mathematics
1 answer:
Nata [24]2 years ago
8 0

Answer:

     y=-2x+7

     y=3x-3

Step-by-step explanation:

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A satellite orbits the Earth with an elliptical orbit modeled by x squared over 43 million eight hundred twenty four thousand fo
morpeh [17]

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is

D= 510 km. Option B. This is further explained below.

<h3>What is Kepler Orbit?</h3>

Generally, In the study of astrodynamics, an ellipse of the satellite is often referred to as a Kepler Orbit

The function of the elliptical orbit is

\frac{(x-h)^2}{a^2}+\frac{(x-k)^2}{b^2}=1

compared to

\frac{(x^2)^2}{47334400}+\frac{(y^2)^2}{43956900}=1

Hence

a = √(47,334,400 km²)

a= 6,880 km.

In conclusion, The distance of the satellite above the Earth's surface.

D = a - r

D= 6,880 km - 6,370 km

D= 510 km

Read more about elliptical orbit

at brainly.com/question/13999216

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7 0
2 years ago
Read 2 more answers
What is the answer to 3/4-3/8?
Norma-Jean [14]
6/8-3/8
3/8
the answer to 3/4-3/8 is 3/8
8 0
3 years ago
Can someone help me please? Maybe give the answers?<br><br><br><br><br><br>Thank you.
pishuonlain [190]

Answer:

Finding the missing number is fairly simple and can be done in a few short steps. I will show you using the 21 / __ fraction.

First, divide the included number by its corresponding number in the original fraction.

21 ÷ 3 = 7

To find what the denominator of this would be, multiply 4 by 7.

4 * 7 = 28

The fraction would be 21 / 28.

This works with both numerators and denominators. If you need more of the answers just ask in the comments.


7 0
2 years ago
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Help plzzzzzzzzzzzzzzzzzzzzz
andreyandreev [35.5K]

Answer:

20??? wow I feel stupid I forgot how to do everything

4 0
2 years ago
Help me ... question is in the picture and the answer choices are
Strike441 [17]

\left(\dfrac{2m+2p}{2},\dfrac{2n+2r}{2}\right)=\left(m+p,n+r\right)

6 0
3 years ago
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