Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
The answer is <span>77.2727272727273% hopw this help
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The answer is 523.6 and all you have to do is round it to the nearest hundredth
Step-by-step answer:
The steps are much easier to follow when we know how many product it sells. The number does not really matter, because we need the profit per item.
Say, the company made and sold 100 items of the product.
The revenue = 100*5 = $500.
On the average, 2 out of 100 are defective and need to be replaced at a cost of $100 each, so
replacement cost = 2* 100 = 200
So net profit for 100 items = $500 -$200 = $300
Net profit for each item = $300/100 = $3.00
Remark: since the product is replaced, no refund is necessary, so revenue stays at $300.
Answer:
Therefore, Steve will paint house for 20.6 days.
Step-by-step explanation:
We know that Steve determines that it would take them 9 days to paint the house together (if they were both healthy) and that it would take Janet (when healthy) 16 days to paint the house alone.
We conclude that in 1 day Janet painted 1/16 of the house. In nine days, Janet painted 9/16 of house.
So, 7/16 of house paint Steve in nine days.
We have the following proportion:
Therefore, Steve will paint house for 20.6 days.
