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Contact [7]
3 years ago
11

Evaluate: 2^-2 x (13x3)-5^3

Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0

2^-2 x (13x3)-5^3

1/ (2^2) * 39 - 125

1/4 *39 -125

39/4 -125

9 3/4 - 125

factor out -1

- (125-9 3/4)

borrow to subtract the fraction

- (124 4/4 - 9 3/4)

- (115 1/4)

-115 1/4

Rainbow [258]3 years ago
3 0

Answer:

-115.25

2^-2 x (13x3)-5^3

2^-2 x (39)- 5^3

2^-2 x (39)- 125

0.25 x (39) - 125

9.75 - 125

-115.25




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pashok25 [27]
1. The function H= -16T^2+80T+5 is a parabola of the form a x^{2} +bx+c, so to find the maximum height of the ball, we are going to find the y-coordinate of the vertex of the parabola. To find the y-coordinate of the vertex we are going to evaluate the function at the point \frac{-b}{2a}.
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We can conclude that the ball reaches a maximum height of 105 feet.

2. Since we now know that the maximum height the ball reaches is 105 feet, we are going to replace h with 105 in our function, then we are going to solve for t to find how long the ball takes to reach its maximum height:
h=-16t^2+80t+5
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t= \frac{5}{2}
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We can conclude that the ball reaches its maximum height in 2.5 seconds.

3. Just like before, we are going to replace h with 5 in our original function, then we are going to solve for t to find how long will take for the ball to be caught 5 feet off the ground:
h=-16t^2+80t+5
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-16t^{2}+80t=0
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t-5=0
t=5

We can conclude that it takes 5 seconds for the ball to be caught 5 feet off the ground.
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