The standard deviation is used in conjunction with the ▼ to numerically describe distributions that are bell shaped. The ▼ varia
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Solution: The standard deviation is used in conjunction with the mean to numerically describe distributions that are bell shaped. The mean measures the center of the distribution, while the standard deviation measures the spread of the distribution.
In normal distribution (bell shaped distribution) , the mean and standard deviation are used to describe its distribution. The mean measures the center of the distribution, while the standard deviation takes care of the spread of the distribution.
The mean of the normal distribution is and the standard deviation is
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The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is
and
We have given that,
f(x) = 2x^2 + x + 4
x g(x)
-2 1
-1 3
0 5
1 7
2 9
<h3>What is a polynomial function?</h3>A polynomial function is a relation where a dependent variable is equal to a polynomial expression.
A polynomial expression is an expression including numbers and variables, where variables are raised to non-negative powers.
The general form of a polynomial expression is:
a₀ + a₁x + a₂x² + a₃x³ + ... + anxⁿ.
The highest power to a variable is the degree of the polynomial expression. When degree = 2, the function is a quadratic function.
When degree = 1, the function is a linear function.
<h3>How do we solve the given question?</h3>
The quadratic function is given to us:f(x) = 2x^2 + x + 4.
We need to determine the linear equation g(x).
Since it's a linear equation we use the two-point method to determine the equation.
<h3>What is the two-point?</h3>y-y₁ = ((y₂-y₁)/(x₂-x₁))*(x-x₁)
We take the points g(-2) =1, g(-1) = 3
g(x) - g(1) = ((g(-2)-g(-1))/(-2+1))*(x-1)or,
g(x) - 1 = ((-2-(-1))/(-2+1))*(x-1)or, g(x) - 1 = -1(-x+1)or,
g(x) = x - 1 + 1 = x
∴ g(x) = x , is the linear function g(x)
We are asked to find the solution to the system of equations f(x) and g(x).To find the solution we need to check what is the common solution to both f(x) and g(x).
For that, we equate f(x) and g(x).2x^2 + x + 4 = x or, 2x² - x +x- 4 = 0or, 2x^2 - 4 = 02(x^2-2)=0x^2-2=0g(-1) = 3(from the table)
The solution to the system of equations that includes quadratic function f(x) and linear function g(x) is and
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