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sergiy2304 [10]

3 years ago

6

on Wednesday 72% of the customers who brought gas at a gas station made an additional purchase there was 250 customer support ga

s how many of these 250 customers made additional purchase (no answer choices)

1 answer:

dmitriy555 [2]3 years ago

8 0

Answer:

180 of the 250 customers !!

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Find the value of n .<br> 6/n = 24/28<br> y = ___.

il63 [147K]

Answer:

$n=7$

Step-by-step explanation:

Cross multiply, isolate the variable, and divide by the coefficient to solve.

$\frac{6}{n}=\frac{24}{28} \\ \\ 24n=168 \\ \\ n=7$

Plug back in to check.

$\frac{6}{7}=0.857142857 \\ \\ \frac{24}{28} =0.857142857$

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4 years ago

Please help me find the answer!!<br><br> Picture ⬇️

expeople1 [14]

Answer:

(1) y≥-3x + 4

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3 years ago

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Which system of equations can be used to find the roots of the equation 4x^2=x^3+2x?

irina [24]

Next time, please share the answer choices.
Starting from scratch, it's possible to find the roots:

<span>4x^2=x^3+2x should be rearranged in descending order by powers of x:

x^3 - 4x^2 + 2x = 0. Factoring out x: </span>x(x^2 - 4x + 2) = 0

Clearly, one root is 0. We must now find the roots of (x^2 - 4x + 2):

Here we could learn a lot by graphing. The graph of y = x^2 - 4x + 2 never touches the x-axis, which tells us that (x^2 - 4x + 2) = 0 has no real roots other than x=0. You could also apply the quadratic formula here; if you do, you'll find that the discriminant is negative, meaning that you have two complex, unequal roots.

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3 years ago

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Ryan has his own business selling watches, and he wants to monitor his profit per watch sold. The expression 200x-300/x models t

ololo11 [35]

Okay I’ll solve this but it’ll take a while to answer but I’ll try my best to finish as fast as I can!

8 0

3 years ago

Write the following function in standard form. Show your work. y=(x-5)(x+5)(2x-1)

Gnesinka [82]

Answer:

$\boxed{y=4x^3-x^2-50x+25}$

Step-by-step explanation:

The given function is

$y=(x-5)(x+5)(2x-1)$

Observe that, the first two factors are from difference of two squares.

$\Rightarrow y=(x^2-5^2)(2x-1)$

$\Rightarrow y=(x^2-25)(2x-1)$

We expand the brackets using the distributive property to obtain;

$\Rightarrow y=2x^2(2x-1)-25(2x-1)$

$\Rightarrow y=4x^3-x^2-50x+25$

The above function is now in standard form, since the terms are arranged in descending powers of $x$ .

4 0

4 years ago