3 years ago

Find the area and perimeter of a rectangle with a length of (6x2-10) and a width of (4x+3)

1 answer:

5 0

Answer:6x2=12-10=2 and 4×+3=12

Step-by-step explanation:

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Allisa [31]

2.1 is already in a decimal form.

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Arlecino [84]

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42 because 3 tens is 30 and 12 ones is 12. so you do 30 + 12 = 42

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Step-by-step explanation:

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Brilliant_brown [7]

Do repeated addition to 1 and 1/2 to get the answer

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amm1812

The easy answer: If, say, B is the zero matrix, i.e.

$B=\begin{bmatrix}0&0\\0&0\end{bmatrix}$

then

$2A=\begin{bmatrix}5&0\\-1&2\end{bmatrix}\implies A=\begin{bmatrix}\dfrac52&0\\\\-\dfrac12&1\end{bmatrix}$

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4 years ago