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disa [49]
3 years ago
9

In the Fibonacci Sequence, each term after the first two terms is the sum of the preceding two terms. If the first two terms are

1 and 1, then what is the tenth term?
Mathematics
1 answer:
Snezhnost [94]3 years ago
5 0

If the first two terms are 1 and 1, then what is the tenth term?

Answer:

The 10th term will be 55

Explanation:

In the Fibonacci Sequence, we add the previous digits to get the next digit. So, here 1st term is 1.

First term= 1

Second term = 0+1= 1

Third term= 1+1=2

Fourth term= 1+2= 3

Fifth term= 2+3= 5

Sixth term= 3+5= 8

Seventh term= 5+8 = 13

Eighth term= 8+13= 21

Ninth term= 13+21= 34

Tenth term= 21+34 = 55

So, the 10th term is 55.

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A group of five people are all working on the same mathematics problem. On the night before it is due, they call each other to d
UkoKoshka [18]

Answer:

Minimum number of calls = 10

Step-by-step explanation:

Lets name the five people as A,B,C,D and E.

<u>On the night before ,each person talks to every other person atleast once that means A would talk to B,C,D and E atleast once.</u>

Lets start with A. He would talk to other 4 people which means there would be 4 phone calls made.

Now lets take B. He can talk to A,C,D and E. But  A has already talked to C therefore to get minimum number of phone calls , B need not call A again. So he calls only C,D and E.

In case of C using similar logic he need to talk to only D and E.

For D , he talks to E alone.

E does not have to talk to anyone as he has already talked to everyone atleast once.

Total calls = 4 + 3 + 2 + 1

                    = 10

5 0
3 years ago
Calls to a customer service center last on average 2.8 minutes with a standard deviation of 1.4 minutes. An operator in the call
Natali5045456 [20]

Answer:

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

n-values of normal variable:

Suppose we have n values from a normally distributed variable. The mean of the sum of all the instances is M = n\mu and the standard deviation is s = \sigma\sqrt{n}

Calls to a customer service center last on average 2.8 minutes.

This means that \mu = 2.8

75 calls each day.

This means that n = 75

What is the expected total amount of time in minutes the operator will spend on the calls each day

This is M, so:

M = n\mu = 75*2.8 = 210

The expected total amount of time the operator will spend on the calls each day is of 210 minutes.

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