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Amanda [17]
4 years ago
11

Can anyone help me with number 8

Mathematics
1 answer:
Vsevolod [243]4 years ago
7 0
The company will charge $15 PLUS $0.12 per mile,x. The equation that shows that statement is: y = $15 + $0.12x
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Which equation(s) below is parallel to y = x-5
PolarNik [594]
2y= 2x - 10 is the correct answer
8 0
3 years ago
Given: ΔABC, where AB = BC Prove: m∠BAC = m∠BCA Statement Reason 1. Let ΔABC be an isosceles triangle with AB = BC. given 2. Cre
weqwewe [10]

Answer:

D. SAS

Step-by-step explanation:

Given: ΔABC

Bisecting <ABC to create point D implies that BD is a common side to  ΔABD and ΔCBD.

Also,

m<ABD = m<CBD (angle bisector)

BA = BC (given property of the isosceles triangle)

Therefore,

ΔABD ≅ ΔCBD (Side Angle Side)

The reason for statement 5 in this proof is that ΔABD ≅ ΔCBD by SAS (Side-Angle-Side) relations of the congruent triangles.

4 0
4 years ago
HELP ME ASAP I NEED HELP PLEASE SOMEONE
scZoUnD [109]

Answer:

welll there no like answers to give here so i dont know might want to check what you post before you post it

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Determine if the card below represents a reflection over the x-axis or a
gtnhenbr [62]

Answer:

Reflection over y-axis

Step-by-step explanation:

We know that with a reflection of the x-axis, we flip the value of the y value

But since the y-values in Q3 and Q4 are both negative, we know that can't be the case

So it has to be a reflection over the y-axis where the x-values are flipped

Hope this helps

7 0
3 years ago
Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC =16 and DC=5 what is the length of BC in the simplest ra
Nana76 [90]

The length of BC is 4 \sqrt{5}.

Solution:

Given ABC is a right triangle.

AC is the hypotenuse and BD is the altitude.

AB and BC are legs of the triangle ABC.

AC = 16 and DC = 5

<u>Leg rule of geometric mean theorem:</u>

$\frac{\text { hypotenuse }}{\text { leg }}=\frac{\text { leg }}{\text { part }}$

$\Rightarrow \frac{AC}{BC}=\frac{BC}{DC}$

$\Rightarrow \frac{16}{x}=\frac{x}{5}$

Do cross multiplication.

\Rightarrow  16\times 5 = x\times x

\Rightarrow  80= x^2

\Rightarrow  16\times 5= x^2

Taking square root on both sides.

\Rightarrow  \sqrt{16\times 5} = \sqrt{x^2}

\Rightarrow  \sqrt{4^2\times 5} = \sqrt{x^2}

square and square roots get canceled, we get

\Rightarrow  4\sqrt{ 5} = x

The length of BC is 4 \sqrt{5}.

7 0
3 years ago
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