Part 1) Find the measures of angle BGEwe know that
The inscribed angle measures half of the arc it comprises.
so
angle BGE=(1/2)*[arc EB]
Part 2) Find the angle BDG
we know that
The measure of the external angle is the semi-difference of the arcs that it covers.
so
angle BDG=(1/2)*[arc GEB-arc GB]
Answer:
(x−1)(x+6)(2x+7); 2x+7
Step-by-step explanation:
2x3+17x2+23x−42
=(x−1)(x+6)(2x+7)
i could just simplify the first part
2 · (x+4)/x-3 Is the answer. I hope it helps.
Answer:
6x - 4
Step-by-step explanation:
For expanding (3x -2) 2 , (3x - 2) is to be multiplied with 2.
(3x - 2) × 2 = 6x - 4