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Vanyuwa [196]
3 years ago
6

PLZ HELPPPP

Mathematics
1 answer:
Lana71 [14]3 years ago
3 0

7 times x to the three fourths power in radical form is Fourth root of quantity 7 times x to the third power.

So, Option C is correct.

Step-by-step explanation:

We need to write 7 times x to the three fourths power in radical form

First writing 7 times x to the three fourths power in mathematical form:

7x^{\frac{3}{4}

Writing it into radical form:

7x^{\frac{3}{4}

We know 1/4 = \sqrt[4]{}

So,

\sqrt[4]{(7x)^3}

Writing it into words:

Fourth root of quantity 7 times x to the third power.

So, 7 times x to the three fourths power in radical form is Fourth root of quantity 7 times x to the third power.

So, Option C is correct.

Keywords: Radical Expression

Learn more about Radical Expression at:

  • brainly.com/question/7153188
  • brainly.com/question/10534381

#learnwithBrainly

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Step-by-step explanation:

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The perimeter of a rectangular garden is 44 meters. The length of the rectangle is 5 less than twice the width. Find the length
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Answer:

  • width: 9 m
  • length: 13 m

Step-by-step explanation:

Let w represent the width. Then the length is 2w-5, and the perimeter is ...

  P = 2(L+W)

  44 = 2((2w-5) +w)

  44 = 6w -10

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The length of the rectangle is 13 meters; the width is 9 meters.

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2 years ago
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Answer:

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The time rate of change of a rabbit population PP is proportional to the square root of PP. At time t=0t=0 (months) the populati
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Answer:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

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If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

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And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

Step-by-step explanation:

For this case we cna use the proportional model given by:

\frac{dP}{dt} = k \sqrt{P}

Where k is a proportional constant, P the population and the represent the number of months

For this case we know the following initial condition P(0) =100 and P'(0) = 10

we can rewrite the differential equation like this:

\frac{dP}{\sqrt{P}} = k dt

And if we integrate both sides we got:

2 \sqrt{P} = kt +C

Where C is a constant., we can rewrite the expression like this:

\sqrt{P} = \frac{1}{2} (kt +C)

If we square both sides we got:

P = \frac{1}{4} (kt +C)^2

If we use the initial condition we have that:

P(0) = 100 = \frac{1}{4} (k*0 +C)^2

And we can solve for C like this:

400 = C^2

C = 20

And now we can find the derivate of the function and we got:

P'(t) = 2* \frac{1}{4} (kt + 20) * k

Using the condition P'(0) = 10 we got:

10 = \frac{1}{2} k (k*0 +20)

20 = 20 k

k= 1

And then the model is defined as:

P = \frac{1}{4} (t +20)^2

And for t =12 months we have:

P(12) = \frac{1}{4} (12 +20)^2 = 256

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