88% not sure but I think so if it’s not the answer I’m sorry.
Hello,
{x=y-3
{x+3y=13;
{x=y-3
{y-3+3y=13;
{x=y-3
{4y=13+3;
{x=y-3
{4y=16;
{x=y-3
{y=16:4=4;
{x=4-3=1
{y=4;
{x=1
{y=4
the solution to the system of equations is (1,4)
Bye :-)
Step-by-step explanation:
![\frac{3x}{x + 1} \div (x + 1) \\ \\ = \frac{3x}{x + 1} \times \frac{1}{(x + 1) } \\ \\ = \frac{3x}{ {(x + 1)}^{2} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B3x%7D%7Bx%20%2B%201%7D%20%20%5Cdiv%20%28x%20%2B%201%29%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B3x%7D%7Bx%20%2B%201%7D%20%20%5Ctimes%20%20%20%5Cfrac%7B1%7D%7B%28x%20%2B%201%29%20%7D%20%20%5C%5C%20%20%5C%5C%20%20%3D%20%20%5Cfrac%7B3x%7D%7B%20%7B%28x%20%2B%201%29%7D%5E%7B2%7D%20%7D%20)
<span>tan(15) =
sin(15) / cos(15) =
sin(45 - 30) / cos(45 - 30) =
[ sin(45)cos(30) - sin(30)cos(45) ] / [ cos(45)cos(30) + sin(45)sin(30)]
Since sin(45) = cos(45) = √2/2, you can just factor that out from the top and bottom
[ cos(30) - sin(30) ] / [ cos(30) + sin(30)]
[ √3/2 - 1/2 ] / [ √3/2 + 1/2]
(√3 - 1) / (√3 + 1)
(√3 - 1)^2 / (√3+1)(√3 - 1)
(√3 - 1)^2 / (3 - 1)
(3 - 2√3 +1) / 2
2 - √3
There's also a formula for tan(a-b), but I couldn't remember it off hand.</span>
Answer:
y=x+5
Step-by-step explanation:
if you mean how many she completed INCLUDING the 5 over the summer