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solniwko [45]
3 years ago
11

How do i solve this equation? W(t)=80-2.5t

Mathematics
1 answer:
Anna007 [38]3 years ago
6 0
W2.5=80 , 80/2.5= 32 t=32
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Jessica can shoot 10 photos in 10 minutes how may photes can she take in 1 hour
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logan enjoys taking his dog to the park. he walks doen hickory st. turns into maple ave. to meet his friend, brett, and then con
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What's the approximate area of a segment of a circle with a height 6 m and the length of the chord is 20 m
storchak [24]
Given:
height = 6m
chord = 20 m

We need to find the radius of the circle.

20 m = 2 √ [ 6m( 2 x radius - 6 m ) ] 
20 m / 2 = 2 √<span>[ 6m( 2 x radius - 6 m ) ] / 2 </span>
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100 m²<span> = 6 m( 2 x radius - 6 m ) </span>
100 m²<span> = 12 m x radius - 36 sq m </span>
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136 m²<span> = 12 m x radius </span>
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<span>11.333 m = radius 
</span>
the area beneath an arc: 

<span>Area = r</span>²<span> x arc cosine [ ( r - h ) / r ] - ( r - h ) x </span>√<span>( 2 x r x h - h</span>²<span> ).
</span>
<span>r</span>²<span> = (11.333 m)</span>²<span> = 128.444 m</span>²<span> </span>
<span>r - h= 11.333 m - 6 m = 5.333 m </span>
<span>r * h = 11.333 m x 6 m = 68 m</span>²

<span>Area = 128.444 m</span>²<span> x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x </span>√<span>[ 2 x 68 m</span>²<span> - 36 m</span>²<span> ] </span>

<span>Area = 128.444 m</span>²<span> x arc cosine [ 0.4706 ] - 5.333 m x </span>√<span> [ 100m</span>²<span> ] </span>

<span>Area = 128.444 m</span>²<span> x 1.0808 radians - 5.333 m x 10 m </span>

<span>Area = 138.828 m</span>²<span> - 53.333 m</span>²<span> </span>

<span>Area = 85.4 m</span>²
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4 years ago
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dybincka [34]
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3 years ago
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Answer:

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Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer/how I got this answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

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