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docker41 [41]
3 years ago
9

II3Find 6 X 915. Show your work.​

Mathematics
1 answer:
love history [14]3 years ago
4 0

Answer:

5490

Step-by-step explanation:

you multiply every number by 6 and you will get the answer

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Solve two step equations: <br><br> 3y +1/5 = 2/5
asambeis [7]

Answer:

y = 1/15

Step-by-step explanation:

3y + 1/5 = 2/5

Subtract 1/5 from each side

3y +1/5 -1/5 = 2/5 -1/5

3y = 1/5

Multiply by 1/3

3y *1/3 = 1/5 *1/3

y = 1/15

5 0
3 years ago
Write the equation for the function graphed below.
S_A_V [24]

Answer:

Yhgrgrifeeefghcrjhrjurir

<h3>Ygceufeleetfej</h3>

7h ch r oh j r4

7 0
3 years ago
Read 2 more answers
Thomas earns a higher pay rate on the number of hours more than 8 that
Yuki888 [10]

The additional percent of his regular pay rate is 82.5% which he earned in the longer shift.

<h3>What is the percentage?</h3>

It is defined as the ratio of two numbers expressed in the fraction of 100 parts. It is the measure to compare two data, the % sign is used to express the percentage.

The longer shift is 12 hours.

Basic pay = $136.00

On a longer shift, Thomas earned = $248.20

The percent in increase:

\rm Percent \ increase = \dfrac{final \ amount - initial \ amount}{initial \ amount}\times 100

\rm Percent \ increase = \dfrac{248.20-136}{136}\times 100

Percent increase = 82.5%

Thus, the additional percent of his regular pay rate is 82.5% which he earned in the longer shift.

Learn more about the percentage here:

brainly.com/question/8011401

#SPJ1

6 0
3 years ago
80 points just please help
Arlecino [84]

Answer:

F

Step-by-step explanation:

If you used the first one

(4÷4) (4÷4) = 1 which is correct.

input the values in the equations and check each one

5 0
3 years ago
Read 2 more answers
Evaluate the given integral by changing to polar coordinates... \int \int_{D}^{}} xy dA ...where D is the disk with center the o
11111nata11111 [884]

Answer:

0

Step-by-step explanation:

If we use polar coordinates, the region D can be covered by replacing (x,y) by (r*sin(Θ),rcosΘ)), with 0<r<7, 0<Θ<2π. The differential matrix

\left[\begin{array}{cc}rcos(\theta)&-rsin(\theta)\\sin(\theta)&cos(\theta)\end{array}\right]

has determinant equal to r, so we can compute the double integral as follows

\int\limits_D {xy} \, dx \, dy =  \int\limits_0^{2\pi}\int\limits_0^r r^3cos(\theta)sin(\theta) \, dr \, d\theta

(Note that we multiplied by the determinant of the Jacobian, r). A primitive for r³ is r⁴/4, thus, for Barrow's rule we have

\int\limits_0^{2\pi}\int\limits_0^r r^3cos(\theta)sin(\theta) \, dr \, d\theta = \int\limits_0^{2\pi}(\frac{r^4}{4}cos(\theta)sin(\theta)) \, |_{r = 0}^{r = 7} \, d\theta

A primitive of cos(Θ)sin(Θ) can be obtained using substitution, and it is sin²(Θ)/2 (note that the derivate of sin²(Θ) is 2sin(Θ)cos(Θ)). Therefore, taking both the dividing 4 and the 2 obtained, we have

\int\limits_0^{2\pi}(\frac{r^4}{4}cos(\theta)sin(\theta)) \, |_{r = 0}^{r = 7} \, d\theta = \frac{1}{8} \int\limits_0^{2\pi} 7^4 * \frac{cos(\theta)sin(\theta)}{2} \, d\theta = \frac{7^4}{8} (sin^2(\theta)) |_{\theta=0}^{\theta=2\pi} \\= \frac{7^4}{8} (sin^2(2\pi)-sin^2(0)) = 0

Hence, the integral is 0.

5 0
3 years ago
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