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3 years ago

How do addition facts help you subtract

2 answers:

8 0

A number fact is made up of three numbers. These three numbers can be used to make up other number facts. Knowing one fact can help children with other facts. Look at the number facts we can make with the numbers 3, 4, and 7.

<span><span>Addition FactsSubtraction Facts</span><span>3 + 4 = 77 – 3 = 4</span><span>4 + 3 = 7<span>7 – 4 = 3</span></span></span>

allsm [11]3 years ago

7 0

Addition facts help to see if the answer to subtraction problems are right by adding.If both the answers are the same,the answer is correct.

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3x^2(4x^3-2x^2+7x-4)

Lunna [17]

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<h3>>> Given Question :</h3>

3x²(4x³ - 2x² + 7x - 4)

<h3>>> Required Solution :</h3>

12x⁵ - 6x⁴ + 21x³ - 12x²

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6 0

3 years ago

one of the students wants to make a tabletop shaped like a right triangle the tabletop will have the same area as the tabletop s

Paha777 [63]

The area of the given figure is equal to the area of a rectangle with sides 5 feets by 6 feets less the area of four square cut-outs of side 1 feet.
Area of the rectangle = 5 x 6 = 30 square feets.
Area of the four square cut-outs = 4(1 x 1) = 4 x 1 = 4 square feet
Area of the given figure = 30 - 4 = 26 square feet.

Area of a triangle = 1/2 x base x height
i.e. 1/2 bh = 26
bh = 26 x 2 = 52
possible values of base and height = (1 and 52), (2 and 26), (4 and 13)

5 0

3 years ago

What is the third term when -2h4+5h2-3-2h-8h3 is arranged in descending order

Oduvanchick [21]

The third term would be 5h2 because the descending order would be
-2h4 - 8h3 + 5h2 - 2h - 3

8 0

3 years ago

Two problems here I need solved! I need every step, so please have that with your answers!!

Free_Kalibri [48]

QUESTION 1

We want to solve,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-6x+8}$

We factor the denominator of the fraction on the right hand side to get,

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x^{2}-4x - 2x+8}.$

This implies
$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{x(x-4) - 2(x - 4)}.$

$\frac{1}{(x-4)}+\frac{x}{(x-2)}=\frac{2}{(x-4)(x - 2)}$

We multiply through by LCM of
$(x-4)(x - 2)$

$(x - 2) + x(x-4) = 2$

We expand to get,

$x - 2 + {x}^{2} - 4x= 2$

We group like terms and equate everything to zero,

${x}^{2} + x - 4x - 2 - 2 = 0$

We split the middle term,

${x}^{2} + - 3x - 4 = 0$

We factor to get,

${x}^{2} + x - 4x- 4 = 0$

$x(x + 1) - 4(x + 1) = 0$

$(x + 1)(x - 4) = 0$

$x + 1 = 0 \: or \: x - 4 = 0$

$x = - 1 \: or \: x = 4$

But
$x = 4$
is not in the domain of the given equation.

It is an extraneous solution.

$\therefore \: x = - 1$
is the only solution.

QUESTION 2

$\sqrt{x+11} -x=-1$

We add x to both sides,

$\sqrt{x+11} =x-1$

We square both sides,

$x + 11 = (x - 1)^{2}$

We expand to get,

$x + 11 = {x}^{2} - 2x + 1$

This implies,

${x}^{2} - 3x - 10 = 0$

We solve this quadratic equation by factorization,

${x}^{2} - 5x + 2x - 10 = 0$

$x(x - 5) + 2(x - 5) = 0$

$(x + 2)(x - 5) = 0$

$x + 2 = 0 \: or \: x - 5 = 0$

$x = - 2 \: or \: x = 5$

But
$x = - 2$
is an extraneous solution

$\therefore \: x = 5$

7 0

3 years ago

Please help! This is i-ready it will probably be easy for you.

Radda [10]

Answer:

Step-by-step explanation:

Your right it is easy 1.50 per pound 1 pound is 16 ounces so to make 32 ounces times it by 2 16 times 2 is 32 you will also times 1.50$ times 2

7 0

3 years ago