Step-by-step explanation:
Total Surface area of a pyramid is given as
= Lateral surface area + area of base.
Lateral surface area = 1/2×perimeter of base×slant height
given the base is square with side 9 in , and slant height of 12 inches.
therefore, LSA = 1/2(9*4)×12 = 216 in^2
Now, TSA = LSA + Base area = 216+9^2 = 297 in^2
a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).
b) It can not be solved as dimensions are missing in the question.
However, the logic has been explained in the soluion one easily put values to find the solution.
Answer:
Step-by-step explanation:
(6x+1)4 = 124
6x+1 = 31
x = 5
I'm going to assume the crust covered by the dosenot matter because the total surface area cannot be found without the depth of the pie.
So the surface are is the area of the top of the pie, the top of the pie is circular and is equal to 2

r²
The diameter is the sum of 2 radii, hence r=8
D=12
= 2r =12
r=8
With the raduis the area can be found
A= 2

r²
A=2

8²
A=2(64)

A=128

If the pie cost 10.99, the cost per inch can be found by dividing the area by cost
cost/inch =128

/10.99
cost/inch =11.64

= 11.64(3.14)
= 36.57
The pie costs 36 cents per square inch