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Liono4ka [1.6K]
3 years ago
14

1 of 4

Mathematics
1 answer:
Serhud [2]3 years ago
4 0
7 Did occurred twice. So 7 is the mode.
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HELP PLLLLLSSSDDSSSSSS
Readme [11.4K]

Answer:

the answer is a.

Step-by-step explanation:

i hope this helps :)

8 0
3 years ago
Larry has $50 in his bank account. He deposits $25 and withdraws $90. What integer represents how much money is now in his accou
Lisa [10]

Answer:

50+25=75 minus 90= -15

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the product of (x + 5)2
tatuchka [14]
You distribute the problem as shown;
2(x+5) 2 times x+2 times 5=2x+10
The answer is 2x+10!
5 0
3 years ago
Using the least number of coins how many quarters, dimes, nickels, and pennies to make $1.74
SpyIntel [72]

Let's use our largest amount (quarter) to see how many can fit evenly into 1.74.

  • 1.74/0.25 = 6.96
  • The most quarters that can fit into $1.74 is 6.

---Multiply $0.25 by 6 = $1.50

---Subtract $1.50 from $1.74 = $0.24

---We need to use the rest of the coins to fill up $0.24.

Now let's use our second largest amount (dime) to see how many can fit evenly into 0.24.

  • 0.24/0.10 = 2.4
  • The most dimes that can fit into $0.24 is 2.

---Multiply $0.10 by 2 = $0.20

---Subtract $0.20 from $0.24 = $0.04

No nickels can fit into $0.04, because they are worth $0.05.

We can use our least amount (pennies) to fill in the $0.04 remaining.

Your answer is 6 quarters, 2 dimes, and 4 pennies.

4 0
3 years ago
A sequence can be generated by using an = an-1 + 4, where a1 = 6 and n is a whole number greater than 1. What are the first four
Firlakuza [10]

<u>Answer:</u>

  • The first four terms are <u>4</u><u>,</u><u>8</u><u>,</u><u>1</u><u>2</u><u>,</u><u>1</u><u>6</u>

<u>Step-by-Step </u><u>Explanation</u><u>:</u>

The given relation between the nth term and it's previous term is given by:

\boxed{an = an - 1 + 4}

GiveN:

  • a1 = 4

Now finding the other three terms of the AP with the given relation.

a2 = a1 + 4

Putting a1 = 4,

a2 =  4 + 4 = 8

Now, Third term:

a3 = a2 + 4

Putting a2 = 8,

a3 = 8 + 4 = 12

Now, Fourth term:

a4 = a3 + 4

Putting a3 = 12,

a4 = 12 + 4 = 16

Hence, The first four terms of the AP is 4, 8, 12 & 16.

7 0
3 years ago
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