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3 years ago

A student is trying to solve the set of two equations given below:

1 answer:

7 0

If you would like to eliminate the z-term, you can do this using the following steps:

x + z = 6 /*(-2)
3x + 2z = 1
_____________
-2x -2z = -12
3x + 2z = 1
_____________
-2x + 3x = -12 + 1
x = -11

The correct result would be x + z = 6 /*(-2).

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2 years ago

Solve the following inequality 5x+12+3x<36

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3 years ago

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3 years ago

The sum of two polynomials is â€"yz2 â€" 3z2 â€" 4y 4. If one of the polynomials is y â€" 4yz2 â€" 3, what is the other polynomi

gtnhenbr [62]

The sum of polynomials involves adding the polynomials

The other polynomial is $y^3 -y^2+ 4y - 1$

The sum of the polynomials is given as:

$Sum = y^3 + 3y^2 + 4y - 4$

One of the polynomials is given as:

$P = 4y^2 - 3$

Represent the other polynomial with Q.

So, we have:

$P +Q =Sum$

Substitute the expressions for P and Sum

$4y^2 - 3 +Q =y^3 + 3y^2 + 4y - 4$

Make Q the subject

$Q =y^3 + 3y^2 -4y^2+ 4y - 4 +3$

Evaluate like terms

$Q =y^3 -y^2+ 4y - 1$

Hence, the other polynomial is $y^3 -y^2+ 4y - 1$