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musickatia [10]

3 years ago

11

Min makes a scale drawing of her rectangular garden using a scale of 1 to 25. Her garden measures 5 meters long by 3 meters wide

. What will the dimensions on the drawing be? (note 1 m = 100cm, change all meters to centimeters to complete this problem) *

1 answer:

Sergio039 [100]3 years ago

8 0

Answer:

500cm x 300cm

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Laura, Jose, and Keith have a total of $118 in their wallets. Jose has $8 more than Laura, Keith has 3 times what Laura has. How

True [87]

Let’s assume that Laura has x$
Jose = 8+ x
Keith= 3x

So the total is equal to
118= x + 8 +x + 3x
118= 5x + 8
Subtract 8 from both sides
110= 5x
Divide 5 by both sides
22$= x which is what Laura has
Jose will have :8+22= 30$
Keith will have :3*22=66$

4 0

3 years ago

Assume that the total revenue received from the sale of x items is given by, R(x)equals34 ln (4 x plus 5 ), while the total c

katen-ka-za [31]

Answer:

63 units

Step-by-step explanation:

The profit function P(x) is given by the revenue function minus the cost function:

$P(x) = R(x) - C(x)\\P(x) = 34ln(x+5)-\frac{x}{2}$

The number of units sold 'x' for which the derivate of the profit function is zero, is the number of units that maximizes profit:

$P(x) = 34ln(x+5)-\frac{x}{2}\\P'(x) =0= \frac{34}{x+5}-\frac{1}{2}\\x+5=68\\x=63\ units$

The number of units that should be manufactured so that profit is maximum is 63 units.

5 0

3 years ago

Ryan gave seven of his model cars to a friend then he bought six more cars now Ryan has 13 cars how many did Ryan start with

Fed [463]

Gave away 7 ⇒ -7

Bought 6 ⇒ + 6

Left with 13

If he did not buy the 6 cars ...
13 - 6 = 7
If he did not give the 7 cars away ...
7 + 7 = 14

He has 14 cars at first.

13 - 6

5 0

3 years ago

What is the greatest common factor of 44c5,22c3 and 11c4?

elena-s [515]

Answer:

The greatest common factor of the given expressions is

$11c^3$

Step-by-step explanation:

Given that $44c^5,22c^3,11c^4$

$44c^5$ can be written as

$11\times 4\times c^3\times c^2$

$22c^3$ can be written as

$11\times 2\times c^3$

and $11c^4$ can be written as

$11\times 1\times c^3\times c$

Comparing the common factors we have $11\times c^3$ is the greatest common factor of $44c^5,22c^3,11c^4$

Therefore the greatest common factor of the given expressions is

$11c^3$

3 0

3 years ago

I don't get how to do this

Degger [83]

Alright so 25% of the 32 students scored an A. 25% is equal to 1/4. So just take a fourth of 32 to get your answer, which is 8.

8 0

3 years ago

Read 2 more answers