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lakkis [162]
3 years ago
8

Is y=-4+1 parallel, perpendicular, or neither to 4*+y=-3

Mathematics
2 answers:
Advocard [28]3 years ago
7 0
I think it’s Prevail because I did the math on my calculator and I’m pretty sure it’s i
frosja888 [35]3 years ago
5 0

4x + y = -3

y = 4x -3

I assume 4 is actually 4x

Parallel = same slope

-4 does not have the same slope as 4

Perpendicular = reciprocal slope

-4 is not the reciprocal of 4

Neither

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A figure in the second quadrant is reflected over the y-axis. In which quadrant will the reflected figure appear?
alukav5142 [94]

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3 0
4 years ago
In a standard deck of cards there 52 cards of which 26 are black and 26 are red. Additionally, there are 4 suits, hearts, clubs,
stich3 [128]

Using probability concepts, it is found that P(S and D) = 0.1275.

-----------------------

  • A probability is the <u>number of desired outcomes divided by the number of desired outcomes</u>.
  • In a standard deck, there are 52 cards.
  • Of those, 13 are spades, and 13 are diamond.

  • The probability of selecting a spade with the first card is 13/52. Then, there is a 13/51 probability of selecting a diamond with the second. The same is valid for diamond then space, which means that the probability is multiplied by 2. Thus, the desired probability is:

P(S \cap D) = 2 \times \frac{13}{52} \times \frac{13}{51} = \frac{2\times 13 \times 13}{52 \times 51} = 0.1275

Thus, P(S and D) = 0.1275.

A similar problem is given at brainly.com/question/12873219

7 0
2 years ago
Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS
olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....

where, n = number of trials (samples) taken = 36 couples

            r = number of success

            p = probability of success which in our question is probability

                   of a girl, i.e.; p = 0.5

<em><u>Let X = Numbers of girls in groups of 36 births </u></em>

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

         <u>Mean</u>, E(X) = n \times p = 36 \times 0.5 = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

        <u>Standard deviation</u>, S.D.(X) =  \sqrt{n\times p\times (1-p)}

                                                      =  \sqrt{36\times 0.5\times (1-0.5)}

                                                      =  3

3 0
3 years ago
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