we have the function
f(x)=6/(7x)
the interval [2,6]
Divide into fur rectangles
the width of each rectangle is equal to
(6-2)/4=1
the intervals are
(2,3) (3,4) (4,5) and (5,6)
using the right endpoints
the approximate area is equal to
A1=f(3)*(1)=[6/(7*3)]*(1)=6/21
A2=f(4)*(1)=[6/(7*4)]*(1)=6/28
A3=f(5)*(1)=[6/(7*5)]*(1)=6/35
A4=f(6)*(1)=[6/(7*6)]*(1)=6/42
therefore
the approximate area is
A=(6/21)+((6/28)+(6/35)+(6/42)
simplify
A=(6/7)*[(1/3)+(1/4)+(1/5)+(1/6)]
A=(6/7)*[(20+15+12+10)/60]
A=(6/7)*[57/60]
<h2>A=57/70 unit2 -----> exact answer</h2>
Answer:
The vertex of the parabola is;
([-1], [3])
Step-by-step explanation:
The given quadratic equation is presented as follows;
x² + 8·y + 2·x - 23 = 0
The equation of the parabola in vertex form is presented as follows;
y = a·(x - h)² + k
Where;
(h, k) = The vertex of the parabola
Therefore, we have;
x² + 8·y + 2·x - 23 = 0
8·y = -x² - 2·x + 23
y = 1/8·(-x² - 2·x + 23)
y = -1/8·(x² + 2·x - 23)
y = -1/8·(x² + 2·x + 1 - 23 - 1) = -1/8·(x² + 2·x + 1 - 24)
y = -1/8·((x + 1)² - 24) = -1/8·(x + 1)² + 3
Therefore, the equation of the parabola in vertex form is y = -1/8·(x + 1)² + 3
Comparing with y = a·(x - h)² + k, we have;
a = -1/8, h = -1, and k = 3
Therefore, the vertex of the parabola, (h, k) = (-1, 3).
Answer:
Step-by-step explanation:
First make all the fractions into decimals
1/5 = 0.2
2/5 = 0.4
As we know non terminating numbers are irrational so make up any non terminating number between 0.2 and 0.4
Like 0.3454672438700894......
Or 0.27435847454706.....
Options are infinite
D.11/24
1/12=2/24
3/8=9/24
2/24+9/24=11/24
D is the correct answer; Divide. Because 20 divided by 4=5, 5+5=10
