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hammer [34]
2 years ago
13

When Paige first enters a dark movie theater, she cannot see well. As her eyes adjust to the darkness, Paige is able to spot an

empty seat. Which sensory receptors enable Paige to see in the dark?
Biology
1 answer:
pshichka [43]2 years ago
5 0
The best answer that is being described above is the RODS. Along with cones, Rods are one of the photo<span>receptor cells in the retina of the </span>eye. Unlike the cones that help with color vision, the rods focuses more on the gray scale, the reason why we can see everything in a gray scale at night or in a dark environment. Hope this helps.
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What are the 2 hormones that are released from the anterior pituitary that influence both the female and male reproductive syste
Yakvenalex [24]
Follicle-stimulating hormones (FSH):
<span><span>·     </span><span>In males-</span> stimulates the form<span>ation of  secondary spermatocytes from </span>primary spermatocytes
</span> <span><span>·     </span><span>In females-</span> stimulates the growth recruitment of immature ovarian follicles in the ovary</span>  

<span> Luteinizing hormones (LH):</span>
<span><span>·     </span>In males- stimulate the Leydig cells to produce testosterone</span>
<span><span>·     </span>In females- stimulates theca cells for estradiol production</span>

Those are only some of the functions of those hormones.   <span>Adrenocorticotropic hormones are hormones produced by pituitary glands which also indirectly have an influence on the reproductive system (male and female).</span>
6 0
3 years ago
Determine whether each of the following is a characteristic of a protist, fungus, or both.
n200080 [17]
Mycelium-Fungi

<span>
Heterotrophic-Both</span>

<span>
Pseudopods-Protists</span>

<span>
Contain cell walls with chitin-Fungi </span>

<span>
Fruiting body-Fungi</span>

<span>
Flagellum-Protists
I hope this helps out alot. </span>

5 0
3 years ago
Read 2 more answers
According to the theory of _____________, mitochondria in cells today are the descendents of aerobic prokaryotes that used oxyge
Viefleur [7K]
I'm pretty sure its endosymbiosis 
6 0
3 years ago
1. What is the total magnification of an object if the ocular lens magnification is 20x and the objective lens magnification is
V125BC [204]

1. Answer: 900x

A typical microscope has two lens: ocular lens which located near the eye, and objective lens which located near the object. The image will undergo magnification of both lens. The total magnification of the object would be the product of both lens multiplication, not the sum. The multiplication will be: 20x * 45x= 900x

total mag= ocular * object

total mag= 20x * 45x

total mag= 900x


2.  Answer: 100x

The total magnification of the object would be the product of both lens multiplication. If the total magnification 1000x, that mean it was the product of ocular lens and objective lens. If ocular lens magnification is 10x, objective lens magnification would be:

total mag= ocular * object

1000x= 10x*object

object=1000x/ 10x=

object=100x

3. Answer: 0.2 mm

The area of the microscope that can be viewed by the eye should be the same. But since the magnification is different, the actual area that it represent will be different. Microscope with bigger magnification will have smaller diameter of the field of view(DFV).  Remember that micrometer(μm) is 1/1000 of millimeter(mm). The DFV would be:500 μm/ ( 1000x/400x)= 200μm= 0.2 mm


4. Answer: 750μm

This question is similar to number 3 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm) .

The DFV of a 10x objective lens is 3 mm. Then the DFV of 40x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 3mm/ ( 40x/10x)= 0.75 mm= 750μm

5. Answer: 125μm x 37.5μm

The lens DFV of microscope from question 4 is 750μm, so the width and length of the area would be 750μm.

If 6 organisms could fit across the DFV if they were laid end-to-end, the length would be: 750μm/ 6 organism= 125μm

If 20 organism could fit is stacked side by-side, then the width would be: 750μm/ 20 organism= 37.5μm

6. Answer: 6mm

This question is similar to number 3 and number 4 question. Remember that 1 millimeter(mm) equal to 1000 micrometer(μm).

The DFV of a 100x objective lens is 1.5 mm. Then the DFV of 25x lens would be:

DFV2= DFV1/ (mag1/mag2)

DFV2= 1.5mm/ (100x/25x)= 6 mm


7.Using the 100x objective lens from question 6, you estimate 12 organisms could fit across the DFV if they were laid end-to-end and 30 could fit is stacked side-by-side. What is the length and width of this organism (in microns)?  

Answer: 0.5mm x 0.2mm or 500μm x 200μm

The lens DFV of microscope from question 6 is 6 mm, so the width and length of the area would be 6 mm.

If 12 organisms could fit across the DFV if they were laid end-to-end, the length would be: 6mm/ 12 organism=0.5mm

If 30 organism could fit is stacked side by-side, then the width would be: 6mm/ 30 organism= 0.2mm

6 0
3 years ago
Hypothesis:
AleksandrR [38]

Answer:

Objective(s):

In your own words, what was the purpose of this lab?

In this lab report, the purpose is that hamsters carry traits fro parents.

Hypothesis:

In this section, please include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.

Test One: If I breed a short fur, FF female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.

All short fur

Test Two: If I breed a short fur, Ff female with a short fur, Ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.

Some short and some long

Test Three: If I breed a long fur, ff female with a long fur, ff male, then I will expect to see (all short fur; some short and some long fur; all long fur) offspring.

All long fur

Procedure:

The procedures are listed in your virtual lab. You do not need to repeat them here. Please be sure to identify the test variable (independent variable) and the outcome variable (dependent variable) for this investigation.

Remember, the test variable is what is changing in this investigation. The outcome variable is what you are measuring in this investigation.

Test variable (independent variable):
Outcome variable (dependent variable):

Data:

Record the data from each trial in the data chart below. Be sure to fill in the chart completely.

Test One

 

 

Parent 1: FF

Parent 2: Ff

 FF

 FF

 Ff

 Ff

Phenotype ratio:

____0____ :

 ___4_____

short fur :

 long fur

Test Two

 

 

Parent 1: Ff

Parent 2: Ff

 FF

 Ff

 Ff

 ff

Phenotype ratio:

1 :

 ____3____

short fur :

 long fur

Test Three

 

 

Parent 1: ff

Parent 2: ff

 ff

 ff

 ff

 ff

Phenotype ratio:

4 :

 ___0_____

short fur :

 long fur

Conclusion:

Your conclusion will include a summary of the lab results and an interpretation of the results. Please write in complete sentences.

1. Which genotype(s) and phenotype for fur length are dominant? FF

2. Which genotype(s) and phenotype for fur length are recessive? ff

3. If you have a hamster with short fur, what possible genotypes could the hamster have? It would probably be Ff or a ff

4. If you have a hamster with long fur, what possible genotypes could the hamster have? It would be Ff or an FF

5. Did your data support your hypotheses? Use evidence to support your answer for each test.

◦ Test One:? ◦ Test Two:?

◦ Test Three:?

6. Which hamsters are the parents of the mystery hamster? Include evidence to prove that they are the correct parents.?

4 0
3 years ago
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