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Citrus2011 [14]
3 years ago
9

Determine whether line segment FG is tangent to circle E. True or False

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0
The tangent line to a circle makes an angle of 90 degrees with the radius.
If |FG| is tangent to circle E. then
30^2 = 26^2 + 17^2
which is not true.
Therefore, line segment FG is not tangent to circle E.
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Michele wanted to measure the height of her school’s flagpole. She placed a mirror on the ground 48 feet from the flagpole, then
yulyashka [42]
Height of the flagpole = x
distance from flagpole to the mirror = 48 ft
height of Michele = 5 ft
distance from Michele to the mirror = 12 ft

Now, set the proportion.

x/48 = 5/12
48 * x/48 = 5/12 * 48
x = 240/12
x = 20

So, the height of the flagpole is 20 ft.

HOPE THIS HELPS!!!!
5 0
3 years ago
Can you guys figure this out please<br> x6∙x∙x3= x6+3 = x9
Marat540 [252]

Answer:

Below.

Step-by-step explanation:

x^6 . x . x^3

= x^6 . x^1 . x^3

= x^(6+1+3)

= x^10.

5 0
3 years ago
Please need some help on this
vredina [299]
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8 0
3 years ago
PLZ HELP FAST multiple choice<br>touching spirit bear​
Juli2301 [7.4K]
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5 0
3 years ago
Use any method to multiply (3a + 2b - c)(a - b + 2c).​
Alla [95]

Answer: 3a^{2}-ab + 5ac- 2b^{2} + 5bc-2c^{2}

Step-by-step explanation:

(3a + 2b − c) (a − b + 2c)  

Expand (3a + 2b − c) (a − b + 2c) by multiplying each  term in the first  expression by each  term in the second expression.

3a ⋅ a + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3 (a ⋅ a) + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 + 3a (−b) + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 + 3 ⋅ −1ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 3a (2c) + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 3 ⋅ 2ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2b (−b) + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b ⋅ b + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1 (b ⋅ b) + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba + 2 ⋅ −1b^2 + 2b (2c) − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2b (2c) − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 2 ⋅ 2bc − ca − c (−b) − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − c (−b) − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca − 1 ⋅ −1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + 1cb − c (2c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − c (2c)

Rewrite using the commutative property of multiplication.

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c ⋅ c

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2 (c ⋅ c)

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 1 ⋅ 2c^2

3a^2 − 3ab + 6ac + 2ba − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − 3ab + 2ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab + 6ac − 2b^2 + 4bc − ca + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 6ac − 1ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + 5ac + cb − 2c^2

3a^2 − ab − 2b^2 + 4bc + bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5bc + 5ac − 2c^2

3a^2 − ab − 2b^2 + 5ac + 5bc − 2c^2

3a^2 − ab + 5ac − 2b^2 + 5bc − 2c^2

6 0
3 years ago
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