Which set of points includes all of the solutions for y = - 3/2x + 2?

Mathematics

1 answer:

Serhud [2]4 years ago

6 0

Answer:

B) (x, - 3/2x + 2) for all real numbers

Step-by-step explanation:

since x can be any real number, there are infinite solutions for y= -3/2x+2 , so the answer is not C or D

for a given x, y can only be y= -3/2*x+2 , not any value y so the answer is not B

since for a given x , y can only be y= -3/2*x+2 the solutions will be (x , y = -3/2*x+2) or (x , -3/2*x+2 ) for all real numbers

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Can someone explain?

makkiz [27]

The correct statement regarding the quadratic function is:

K. I, II and III.

<h3>What is a quadratic function?</h3>

A quadratic function is given according to the following rule:

$y = ax^2 + bx + c$

If a > 0, it has a maximum value, and if a < 0, it has a minimum value.

The extreme value is $(x_v,y_v)$ , in which:

$x_v = -\frac{b}{2a}$

$y_v = -\frac{\Delta}{4a}$

$\Delta = b^2 - 4ac$

The solutions are:

$x_1 = \frac{-b + \sqrt{\Delta}}{2a}$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a}$

In this problem, we have a function h(t). Changing the coefficient c, the h-intercept h(0) changes. Looking at the formulas in the bullet point, the value of $\Delta$ changes, meaning that both the maximum value $y_v$ and the t-intercepts $t_1$ and $t_2$ will change, so option K is correct.