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krok68 [10]
3 years ago
9

Dave drives to work each morning at about the same time. His commute time is normally distributed with a mean of 38 minutes and

a standard deviation of 5 minutes. The percentage of time that his commute time exceeds 44 minutes is equal to the area under the standard normal curve that lies to the ___ of ___.
Mathematics
1 answer:
Gekata [30.6K]3 years ago
8 0

Answer:

Right of z = 1.2

Step-by-step explanation:

Population mean (μ) = 38 minutes

Standard deviation (σ) = 5 minutes

The z-score for any given time X is described by:

z=\frac{X-\mu}{\sigma}

For X = 44 minutes:

z=\frac{44-38}{5}\\z= 1.2

Z-scores to the right of 1.2 will represent times over 44 minutes.

Therefore, the percentage of time in which Dave's commute will exceed 44 minutes is the area under the standard normal curve that lies to the right of z=1.2

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Find the 20th term from the last term of the AP:3,8,13,..., 253. <br>​
RoseWind [281]

Answer:

158

Step-by-step explanation:

The sequence is 3, 8, 13, ..., 253.

Going backwards, it's 253, 248, 243, ..., 3.

First term is 253, common difference is -5.

The nth term is:

a = 253 − 5(n − 1)

The 20th term is:

a = 253 − 5(20 − 1)

a = 158

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Give. b(x) = |x + 4| what is b(-10)
lesantik [10]

Answer:

6

Step-by-step explanation:

b(x) = |x + 4|

b(-10) = |-10 + 4|

-10 + 4 = -6

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3 years ago
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A hotel offers two activity packages. One costs $192 and includes 3 h
matrenka [14]

Answer:

Cost of 1 hour of horseback riding is $30 and cost of 1 hour of parasailing is $51.


Step-by-step explanation:

Let cost of horseback riding be  h

Let cost of parasailing be  p

  • <u>"</u><u>First Package</u><u> costs $192 and includes 3 h  of horseback riding and 2 h of parasailing. "</u>

We can write 3h+2p=192

  • <u>"</u><u>Second Package</u><u> costs $192 and includes 3 h  of horseback riding and 2 h of parasailing. "</u>

We can write 2h+3p=213


<em>Solving these 2 equations simultaneously will give us </em><em>cost of horseback riding for 1 hours [h]</em><em> and </em><em>cost of parasailing for 1 hours [p]</em><em>.</em>

Solving for  h  in Equation 1 and substituting that in Equation 2, we can solve for  p :

3h+2p=192\\3h=192-2p\\h=\frac{192-2p}{3}

2(\frac{192-2p}{3})+3p=213\\\frac{384-4p}{3}+3p=213\\\frac{384-4p+9p}{3}=213\\384+5p=639\\5p=639-384\\5p=255\\p=51

<em>Now, taking the value  p=51 and putting it in either equation and solving for  h  will give us the value of  h  . Let's substitute it into </em><em>Equation 1</em><em>:</em>

3h+2(51)=192\\3h+102=192\\3h=192-102\\3h=90\\h=30


Hence, cost of 1 hour of horseback riding is $30 and cost of 1 hour of parasailing is $51.


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