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3 years ago

Select the correct answer.

Mathematics

1 answer:

Flura [38]3 years ago

4 0

The answer is B good luck bro

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Need help ASAP!!!!! I WILL GIVE THE MOST BRAINLIEST TO THE FIRST PERSON THAT ANSWERS

lys-0071 [83]

Answer:

$x^2 + 10x + y^2 -4y + -7 = 0$

Step-by-step explanation:

For any circle point with coordinate of center (a,b) and radius r

equation of circle is given by

$(x-a)^2 + (y-b)^2 = r^2$

_______________________________________

Given

coordinate of center = (-5,2)

radius = 6

thus, equation of circle can be written by substituting a and b with (-5 ,2) and r =6 as shown below

$(x-a)^2 + (y-b)^2 = r^2\\(x-(-5))^2 + (y-2)^2 = 6^2\\x^2 + 10x + 25 + y^2 -4y + 4 = 36\\=>x^2 + 10x + y^2 -4y + 29 = 36\\=>x^2 + 10x + y^2 -4y + 29 -36 = 36 -36\\=>x^2 + 10x + y^2 -4y + -7 = 0$

Thus, equation of circle is $x^2 + 10x + y^2 -4y + -7 = 0$

3 0

3 years ago

How to find the area of the base of a cone

Gre4nikov [31]

Answer:

Step-by-step explanation:

The base of a cone is simply a circle.

The formula for the area of a circle is A = πr^2.

Example: What is the area of the base of a cone, if the radius of the base is 5 cm?

Answer: A = π(5 cm)^2 = 25π cm^2

7 0

2 years ago

Will give brainliest to whoever answers!!!

jarptica [38.1K]

(A)

Step-by-step explanation:

All other choices will result in a negative number inside the radical sign.

4 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

2 years ago

Simplify. 5x^3/(7x^3+x^4)

Mashutka [201]

Hello,

$\frac{5 x^{3} }{7 x^{3} + x^{4} } = \frac{5 x^{3} }{x^{3}(7+x) }=\frac{5} {7+x}$

Answer Almost A with parenthesis

5/(7+x)

6 0

3 years ago