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Dmitry_Shevchenko [17]
3 years ago
13

The function of c=p+. 07p relates the price of an item p with its cost c after 7% tax and s added. A student has $12.50. What is

the cost of the most expensive item he can buy?
Mathematics
1 answer:
disa [49]3 years ago
7 0

If you have $12.50 to spend, what is the cost of the most expensive item that you can buy? ... The sales tax in TN on nonfood items is 7%. .... Write a function rule to describe each situation The sellings price s(c) after a 45% markup ..... you want to write a program to calculate the total cost of an item that has sales tax added.


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When graphing the inequality y ≤ 2x − 4, the boundary line needs to be graphed first. Which graph correctly shows the boundary l
Volgvan

Answer:

See Below

Step-by-step explanation:

The boundary line follows the graph of y = 2x - 4 because it represents the line of maximum or minimum values the graph could take. y = 2x - 4 has a y-intercept of -4 because it is in slope-intercept form. It also has a slope of 2, so to find another point on the line, you can go up two and right one. Also, this inequality has a solid line because it is "less than or equal to" and a solid line represents the values that equal.

6 0
3 years ago
The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had th
Maru [420]

Student 4 has the largest percent error.

Step-by-step explanation:

The percent error of a measurement is given by

p=\frac{|x-x_{true}|}{x_{true}}\cdot 100

where

x is the value of the measurement

x_{true} is the actual value

For student 1:

x=49\\x_{true}=50

Percent error:

p=\frac{|49-50|}{50}\cdot 100=0.02\cdot 100=2\%

For student 2:

x=25.5\\x_{true}=25

Percent error:

p=\frac{|25.5-25|}{25.5}\cdot 100=0.0196\cdot 100 = 1.96\%

For student 3:

x=7.5\\x_{true}=8

Percent error:

p=\frac{|7.5-8|}{8}\cdot 100=0.0625\cdot 100 = 6.25\%

For student 4:

x=2.1\\x_{true}=1.6

Percent error:

p=\frac{|2.1-1.6|}{1.6}\cdot 100=0.3125\cdot 100 = 31.25\%

So, student 4 has the largest percent error.

Learn more about errors:

brainly.com/question/2764830

#LearnwithBrainly

4 0
4 years ago
Solve 73 make sure to also define the limits in the parts a and b
Aleks04 [339]

73.

f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}

a)

\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3

b)

Since we can't divide by zero, we need to find when:

x^4-2x^2+144=0

But before, we can factor the numerator and the denominator:

\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}

Now, we can conclude that the vertical asymptotes are located at:

\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}

so, for x = -3:

\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty

For x = 4:

\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty

4 0
1 year ago
Callie has 83 postcard
yuradex [85]
Any second part or anything else to look at?
3 0
3 years ago
This triangle is being rotated. The square where the three triangles meet is called the
vagabundo [1.1K]

Answer:

center point

Step-by-step explanation:

use quizlet

5 0
3 years ago
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