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timurjin [86]
3 years ago
9

Solve the equation: 3y - 7 = 5y + 21? Question 1 options: -20 -14 -7/2 14

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0
Y=-14 first subtract 3y to get -7=2y+21then subtract 21 to get -28=2y then divide 2
Paraphin [41]3 years ago
3 0
3y-7=5y+21
+7. +7
3y=5y+28
-5y -5y
-2y=28
Y= -14
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Answer:

The answer should be 25.

Step-by-step explanation:

Since we can rule out 25.4 for being too high, and 22 for being too low, the answer must be 25

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All of the Questions are solved on the images shown below. These images are from Microsoft Whiteboard that I created.

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Answer:

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Step-by-step explanation:

Given equation:

\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1

Add the numerators and keep the denominator so that there is now one fraction:

\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1

Simplify the numerator by expanding the brackets:

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\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1

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Therefore:

\implies 3x=0 \implies x=0

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Therefore, x = 0 or x = 1

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