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astraxan [27]
3 years ago
9

Question 8

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
3 0

Answer:

  third choice of those listed here

Step-by-step explanation:

Match the given statement to the pattern:

  if H, then C.

__

<em>   </em>If <em>you take a class in television broadcasting, </em>then <em>you will film a sporting event</em>

You should be able to see ...

  H: <em>you take a class in television broadcasting</em>

  C: <em>you will film a sporting event</em>

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Ez question i just want ppl to have brainlest Question 2(Multiple Choice Worth 4 points)
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2 years ago
Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a
Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.65, n = 153. So

\mu = E(X) = 153*0.65 = 99.45

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.65*0.35} = 5.9

Consider the probability that greater than 94 out of 153 people will not get the flu this winter

This probability is 1 subtracted by the pvalue of Z when X = 94. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 99.45}{5.9}

Z = -0.92

Z = -0.92 has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

7 0
3 years ago
What is the area of the triangle?
EleoNora [17]
I say A=b*h 
=312 hope this helps

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3 years ago
HELP!<br> Simplify this radical.
Usimov [2.4K]
The simplified answer to that radical is attached

5 0
3 years ago
A worker earns $5.15/h receives a raise. She now earns $6/h. Find the percent of increase in her hourly rate of pay.
Svetllana [295]

Answer:

The percentage increase in worker wages in hourly rate of pay is 16.5%

Step-by-step explanation:

Given as :

The Initial wages earn by worker = $ 5.15 per hour

The Final wages earn by worker = $ 6 per hour

Let The percentage increase in her hourly rate of pay = x %

Now, According to question

x % = \dfrac{\textrm Final earning - \textrm Initail earning}{\textrm Initial earning}

or, x =  \dfrac{\textrm $ 6 - \textrm $ 5.15}{\textrm $ 5.15} × 100

or, x = \frac{0.85}{5.15} × 100

or, x = 0.165 × 100

∴   x = 16.5%

So , Percentage increase in wages = x = 16.5 %

Hence The percentage increase in worker wages in hourly rate of pay is 16.5% Answer

5 0
3 years ago
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