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vfiekz [6]
3 years ago
7

∠A and ​ ∠B ​ are vertical angles with  m∠A=x and  m∠B=4x−30 . What is m∠A ? Enter your answer in the box.

Mathematics
2 answers:
Paul [167]3 years ago
3 0
First off, if they’re vertical angles, they have to be congruent. So set the equation up as x=4x-30. Then solve and get the answer of x=10. Therefore your angle measure is 10 degrees
Tomtit [17]3 years ago
3 0

Answer:

x = 4x -30

We can solve for x subtracting x on both sides:

x-x= 4x-x-30

And then we can add 30 in both sides:

30= 3x

And dividing both sides by 3 we got:

x = 10

Step-by-step explanation:

For this case we know the measure of two angles:

m

m

And we know that both angles are vertical and by definition vertical angles are the angles opposite each other when two lines cross.

For this case since both angles are vertical we have the property that:

m

And replacing what we got we have:

x = 4x -30

We can solve for x subtracting x on both sides:

x-x= 4x-x-30

And then we can add 30 in both sides:

30= 3x

And dividing both sides by 3 we got:

x = 10

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3 0
3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
ANEK [815]

Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
3 years ago
On a number line, the distance from zero to -7 is 7 units.
aivan3 [116]

Answer: Option A. |-7| = 7


Solution:

The distance is a positive value, then we must not take in account the sign, and using:

|a| =-a if a<0

with a=-7

|-7| = -(-7)

|-7| = 7

4 0
3 years ago
HELP TIMED QUESTION !!!!<br> Simplify (5x^3y)^2(-2x^5y^1)
Liono4ka [1.6K]

Answer:

 ( -5•2x8y)

Step-by-step explanation:

Changes made to your input should not affect the solution:

(1): "^-1" was replaced by "^(-1)".

Equation at the end of step 1

 ((5•(x3))•(y2))•(0-(2x5•y(-1)))

Equation at the end of step

 (5x3 • y2) •  -2x5y(-1)

Multiplying exponential expressions :

3.1    x3 multiplied by x5 = x(3 + 5) = x8

Multiplying exponential expressions :

3.2    y2 multiplied by y(-1) = y(2 + (-1)) = y1 = y

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Answer:

D

Step-by-step explanation:

It should be D

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3 years ago
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