Question

Jack picked 76 apples. Of these, he sold 4y apples to Juanita and 3t apples to Sylvia. If he kept the remaining apples, how many apples did he keep? (t and y are positive integers.) (1) y ≥ 15 and t = 2 (2) y = 17

Answer 1

Answer:

Number of apples remaining with him will be 2 when we combined both the conditions.

Step-by-step explanation:

Given;

Number of apples Jack Picked =76

Number of apples sold to Juanita = 4y

Number of apples sold to Sylvia = 3t

We need to find the Number of apples remaining with him.

Solution:

To find the Number of apples remaining with him we will Subtract Number of apples sold to Juanita and Number of apples sold to Sylvia from Number of apples Jack Picked.

framing in equation form we get;

Number of apples remaining with him = $76-4y-3t$

Now Given:

Condition 1 : y ≥ 15 and t = 2

So we can assume y =16 and t =2

Number of apples remaining with him = $76-4\times16-3\times2 = 76 -64 -6 = 6$

Also we can say that y =17 and t =2

Number of apples remaining with him = $76-4\times17-3\times2 = 76 -68 -6 = 2$

So the Given data is Insufficient to find the Number of apples remaining with him.

Condition 2 : y = 17

Number of apples remaining with him = $76-4\times17-3t = 76 -68 -3t = 8-3t$

Since value of t is not given we can say that;

Given data is insufficient to find the number of apples remaining with him.

Condition 3 : Combined i.e y = 17 and y≥ 15 t = 2

Number of apples remaining with him = $76-4\times17-3\times2 = 76 -68 -6 = 2$

Hence we can say that Number of apples remaining with him will be 2 when we combined both the conditions.