There are total of 5 digits, of which we arrange 3 of them.
Therefore using permutations we can find total possible 3-number combinations.
5P3 = 5*4*3 = 60
To be greater than 600 means first digit must be 6. (1 possibility)
A number is even only if last digit is even, 2 or 4. (2 possibilities)
The 2nd digit then can only be 3,5, (2 or 4). (3 possibilities)
The total possible even 3-digit numbers greater than 600 is product of each digit's possibilities.
---> 1*3*2 = 6
Therefore probability is 6/60 = 1/10.
About 224.7 I think. I hope this helps
Answer:
d = -12
Step-by-step explanation:
Add -8 -5 +7
take that number : -6
72 divided by -6 = -12
d = -12
Answer:
<u>(2) x </u>
<u> 4</u>
Step-by-step explanation:
Given the sqrt(x), x zero
So, given sqrt(x -4), x -4 0
Now solve for x
x - 4 0
x 4
