Construct the perpendicular bisector of one side of triangle
Construct the perpendicular bisector of another side
Where they cross is the center of the Circumscribed circle
Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle!
Answer:
Step-by-step explanation:
Answer:
(x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb R
Step-by-step explanation:
4x-6y=-26
-2x+3y-13
4x-6y=-26
x=-13/2+3/2y
4(-13/2+3/2y) - 6y=-26
y in mathbb R
x, y) = (- 13/2 + 3/2 * y, y) ,y in mathbb
Sn = (a1) x (1 - r^n) / (1 - r)
Substituting the known values:
S5 = (6) x (1 - (1/3)^5) / (1 - 1/3) = 242/27 = 8 24/27 = 8 8/9
Answer: Hey I looked on a graphing calculator on Desmos, and its seems that this is increasing.
Step-by-step explanation:
