Ask question

Ask question

All categories

3 years ago

10

A closed container has 7.05 ⋅ 1023 atoms of a gas. Each atom of the gas weighs 1.67 ⋅ 10-24 grams. Which of the following shows

and explains the approximate total mass, in grams, of all the atoms of the gas in the container?
A. 0.87 grams, because (7.05 + 1.67) ⋅ (1023 ⋅ 10-24 ) = 8.72 ⋅ 10-1

B.1.18 grams, because (7.05 ⋅ 1.67) ⋅ (1023 ⋅ 10-24 ) = 11.7735 ⋅ 10-1

C. 8.72 grams, because (7.05 + 1.67) ⋅ (1023 ⋅ 10-24 ) = 8.72

D. 11.77 grams, because (7.05 ⋅ 1.67) ⋅ (1023 ⋅ 10-24 ) = 11.7735 Question 16

Multiple Choice Worth 1 points

2 answers:

mezya [45]3 years ago

5 0

<span>D. 11.77 grams, because (7.05 ⋅ 1.67) ⋅ (1023 ⋅ 10-24 ) = 11.7735 Question 16
</span>

____ [38]3 years ago

3 0

<h2>D. is the correct answer</h2>

D. is correct because when you add up (7.05 ⋅ 1.67) ⋅ (10*23 ⋅ 10-*24 ), you really get = 11.7735.

:)

Hope this Helps!!!

Sorry if I'm a little late..... (2 years) JK!!! LOL!!!!

You might be interested in

Factorize: a^2+10ab -75b^2

soldier1979 [14.2K]

Answer:

9

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

a house was purchased for $150,000 the value decreased by 16% how much is the value of the house now

TiliK225 [7]

Answer:

$126,000

Step-by-step explanation:

16% of 150,000 is 24,000

150,000-24,000=126,000

8 0

3 years ago

Suppose that \nabla f(x,y,z) = 2xyze^{x^2}\mathbf{i} + ze^{x^2}\mathbf{j} + ye^{x^2}\mathbf{k}. if f(0,0,0) = 2, find f(1,1,1).

lesya [120]

The simplest path from (0, 0, 0) to (1, 1, 1) is a straight line, denoted $C$ , which we can parameterize by the vector-valued function,

$\mathbf r(t)=(1-t)(\mathbf i+\mathbf j+\mathbf k)$

for $0\le t\le1$ , which has differential

$\mathrm d\mathbf r=-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

Then with $x(t)=y(t)=z(t)=1-t$ , we have

$\displaystyle\int_{\mathcal C}\nabla f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\nabla f(x(t),y(t),z(t))\cdot\mathrm d\mathbf r$

$=\displaystyle\int_{t=0}^{t=1}\left(2(1-t)^3e^{(1-t)^2}\,\mathbf i+(1-t)e^{(1-t)^2}\,\mathbf j+(1-t)e^{(1-t)^2}\,\mathbf k\right)\cdot-(\mathbf i+\mathbf j+\mathbf k)\,\mathrm dt$

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)(t^2-2t+2)\,\mathrm dt$

Complete the square in the quadratic term of the integrand: $t^2-2t+2=(t-1)^2+1=(1-t)^2+1$ , then in the integral we substitute $u=1-t$ :

$\displaystyle=-2\int_{t=0}^{t=1}e^{(1-t)^2}(1-t)((1-t)^2+1)\,\mathrm dt$

$\displaystyle=-2\int_{u=0}^{u=1}e^{u^2}u(u^2+1)\,\mathrm du$

Make another substitution of $v=u^2$ :

$\displaystyle=-\int_{v=0}^{v=1}e^v(v+1)\,\mathrm dv$

Integrate by parts, taking

$r=v+1\implies\mathrm dr=\mathrm dv$

$\mathrm ds=e^v\,\mathrm dv\implies s=e^v$

$\displaystyle=-e^v(v+1)\bigg|_{v=0}^{v=1}+\int_{v=0}^{v=1}e^v\,\mathrm dv$

$\displaystyle=-(2e-1)+(e-1)=-e$

So, we have by the fundamental theorem of calculus that

$\displaystyle\int_C\nabla f(x,y,z)\cdot\mathrm d\mathbf r=f(1,1,1)-f(0,0,0)$

$\implies-e=f(1,1,1)-2$

$\implies f(1,1,1)=2-e$

3 0

3 years ago

Give brainliest answer Nadal invests $5,678 at an annual interest rate of 4.5 percent for 6 years. For which variable can Nadal

VARVARA [1.3K]

5678(1+(0.045×6))
5678=P as it is the principal amount

8 0

3 years ago

Read 2 more answers

PLEASe HELP I DONT WANT TO WASTE MY POINTS

QveST [7]

Answer:

4 or 5

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers